No because zinc is more reactive than tin so it dilutes it
electrolyte.electrolyteIn solution
If cells are placed in a hypotonic solution the cells gain water. The hypotonic solution has lower solute concentration then the cell's cytoplasm so the water will enter via osmosis.
The energy needed to support the endothermic reaction is supplied by the solution; thus the solution temperaturedecreases.If the reaction were exothermic, the solution temperature would increase.
In general, cooling a solution slows the reaction. You can use the Arrhenius equation to figure out what effect a given temperature will have on a particular reaction (you'll need to know the activation energy).
It would shrivel up and die, because water would flow out of the cell.
The balanced equation for silver wire (Ag) placed in a cadmium nitrate solution would be: Ag(s) + Cd(NO3)2(aq) → AgNO3(aq) + Cd(s)
When tin is placed into a magnesium sulfate solution, no reaction occurs since tin is lower in the reactivity series than magnesium. Tin does not displace magnesium from its salt solution.
it would burst
Nothing. There would be no gradient between the cell and the solution.
electrolyte.electrolyteIn solution
When a cell is placed in a Hypotonic solution, the water diffuses into the cell, causing the cell to swell and possibly explode.
Yes, a reaction would occur as zinc is more reactive than tin. Zinc would displace tin in the reaction, producing zinc ions in solution and solid tin as a result of a single displacement reaction. This reaction would lead to the formation of zinc oxide and hydrogen gas.
The pH of the solution could change during an enzymatic reaction. It could either increase or decrease depending on the specific reaction and the components involved.
The reaction is:Mg + 2 HCl = MgCl2 + H2(g)You will see a release of hydrogen if a lighted match is placed near the test tube - you hear a click.
a really concentrated solution would undergo a reaction quiet dramatically. the colour of the solution would be darker
If the Na2S2O3 solution were omitted, the appearance of the solution would not change significantly for each kinetic trial. Na2S2O3 is a reagent that acts as a reducing agent and is not directly involved in the appearance of the reaction solution. Its absence would likely affect the reaction rate rather than the visual appearance of the solution.
It would get salty! duhhh