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A girl delivering newspapers covers her route by traveling 3.00 blocks west 4.00 blocks north then 6.00 blocks east what is her displacement?
Wiki User
∙ 12y ago
A girl delivering newspapers covers her route by traveling 10.00 blocks west, 4.00 blocks north, and then 2.00 blocks east
Opposite = 4 (related to y axis on 4 blocks north)
Adjacent = 8 (related to x axis on 10 b west - 2 blocks east)
tan -1 x (4/8)
tan theta - 26.6 degrees
since you are looking for the hypotenuse, then sin theta = opp/hyp
sin 26.6=4/hypotenuse
4/sin(26.6) = 8.9 blocks
Wiki User
∙ 15y ago
The girl's displacement can be calculated by finding the net distance and direction from her starting point to her ending point. Using the Pythagorean theorem, her displacement would be approximately 5.00 blocks in a northeast direction.
Wiki User
∙ 12y agoa) Displacement: 4.00 blocks north + (6.00-3.00)=
4.00 blocks north/ 3.00 blocks east= total displacement
b) Total Distance: 3.00 + 4.00 + 6.00= 13.00 blocks
Wiki User
∙ 13y ago(6-3)^2 - 4^2= d^2
d^2=9+16
= 25
d=5 blocks
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