well, there is no ageing requirement to have a retaner,but you do need it after you dont wear braces
I don't know if he still does but he did.
yes if you search google, you can see pics of people with both
retaner baby
if you ate something plastic, you pooped it out
You have some serious problems..........
You probably mean Arnie, Anyway Arnie is the special retaner of the mushroom kingdom. He was first seen in Rise of the mushroom kingdom 4. Arnie is not the mushroom retaner who helped up Mario from his fall in the first Rise of the mushroom kingdom. When out on a hike, Arnie's dad's where not looking, Arnie ate poisonous mushroom's. That gave him irreversible brain damage. Arnie was in a coma for 7 days before he woke up. Arnie has 2 special movie's on the internet 1. Arnie's mis-adventure's. 2. Everyone loves Arnie. Arnie has been seen in a few VGDC movies. Arnie got his name from his dad's favorite movie, " What's Eating Gilbert Grape? ". Remember, Arnie is only seen twice in ROTMK 4. ( :
OLD LADY, OLD HAGE, OLD BOY, OLD MAN,OLD KID,OLD DOG ,OLD GIRL, OLD CAT ,OLD WOLF,and thats all folks
old is 50+ and very old (old old) is 80+.
a old person is qualified to be old when there over the age of 60 years old.
old as your grandma, if shes dead then..i have no idea
You are 0 years old. You are 5 months old. You are 20 weeks old. You are 135 days old. You are 3,252 hours old
The original question was too long to copy in. It was: "The sum of the ages of Old and Young is 48. Old is twice as old as young was when old was half as old as young will be when young is three times as old as old was when old was three times as old as young How old is old?" There is a rather strenuous algebraic solution.The answer is :Old is 30, Young is 18When Old was 18, Young was 6; when Old was 27 (1/2 of 54), Young was 15, and Old is twice that.If you change the sum to 32, then the ages become 20 and 12.When Old was 12, Young was 4; when Old was 18 (1/2 of 36), Young was 10.In each case, Old is always 5/3 as old as Young and 5/8 of the sum.