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ExxonMobil is Big Indian Oil and Development Compny now part of Moblenand is stock in Big Indian of any value?
It seems there may be some confusion in your question regarding ExxonMobil, Indian Oil, and the fictional "Moblenand." If you're asking about the stock value of Indian Oil or a related company, it's important to check current stock market data for accurate information. If "Big Indian" refers to an investment or company context, clarity on its operations and financials would be needed to assess any potential value.
Which is a Pure play company in oil industry?
Frontier Oil Co, Continental Resources, ExxonMobil and Plains All American can all be considered to fall within the "Oil Industry" but to be a little more helpful, one should decide on which component of the oil industry to focus on i.e refiners, drilling/exploration/production, pipeline/transportation/marketing, or fully integrated oil companies. The above examples would fall into these more specific classes of oil companies as follows: Pure Play Refiner: Frontier Oil Company Pure Play Driller/Producer: Continental Resources Pure Play Tranporter/Pipeliner : Plains All American Pure Play fully integrated oil company: ExxonMobil
What are some examples of modern day monopolies?
<p>Debeers, Microsoft<p>
Who owns B P oil company?
British Petroleum is a corporation, so no one person owns it. It does have a president, a chairman and a board of directors who make the critical decisions for the company. The corporation issues stock, and the owners of the stock have some control as they must approve the nominated leaders of the corporation.
What are the advantages of starting your own business?
Some advantages of starting your own business:be your own bosschoose your own hoursprofit
What US companies does China own?
ExxonMobil Procter & Gamble
What is the population of ExxonMobil?
The population of ExxonMobil is 83,600.
What is ExxonMobil's population?
The population of ExxonMobil is 2,010.
If A and B are independent events then are A and B' independent?
if P(A)>0 then P(B'|A)=1-P(B|A) so P(A intersect B')=P(A)P(B'|A)=P(A)[1-P(B|A)] =P(A)[1-P(B)] =P(A)P(B') the definition of independent events is if P(A intersect B')=P(A)P(B') that is the proof
What companies is Exxon Mobile the parent company of?
ExxonMobil is a parent company to ExxonMobil Exploration Company, ExxonMobil Development Company, ExxonMobil Production Company, and many other companies.
What is the product rule and the sum rule of probability?
Sum Rule: P(A) = \sum_{B} P(A,B) Product Rule: P(A , B) = P(A) P(B|A) or P(A, B)=P(B) P(A|B) [P(A|B) means probability of A given that B has occurred] P(A, B) = P(A) P(B) , if A and B are independent events.
When was ExxonMobil Building created?
ExxonMobil Building was created in 1963.
When was ExxonMobil created?
ExxonMobil was created on 1999-11-30.
What is the formula for inclusive events?
The probability of inclusive events A or B occurring is given by P(A or B) = P(A) + P(B) - P(A and B), where P(A) and P(B) represent the probabilities of events A and B occurring, respectively.
How do you find P A given B?
P(A|B)= P(A n B) / P(B) P(A n B) = probability of both A and B happening to check for independence you see if P(A|B) = P(B)
Addition rule for probability of events A and B?
If they're disjoint events: P(A and B) = P(A) + P(B) Generally: P(A and B) = P(A) + P(B) - P(A|B)
Give the example of why probabilities of A given B and B given A are not same?
Let's try this example (best conceived of as a squared 2x2 table with sums to the side). The comma here is an AND logical operator. P(A, B) = 0.1 P(A, non-B) = 0.4 P(non-A, B) = 0.3 P(non-A, non-B) = 0.2 then P(A) and P(B) are obtained by summing on the different sides of the table: P(A) = P(A, B) + P(A, non-B) = 0.1 + 0.4 = 0.5 P(B) = P(A,B) + P(non-A, B) = 0.1 + 0.3 = 0.4 so P(A given B) = P (A, B) / P (B) = 0.1 / 0.4 = 0.25 also written P(A|B) P(B given A) = P (A,B) / P (A) = 0.1 / 0.5 = 0.2 The difference comes from the different negated events added to form the whole P(A) and P(B). If P(A, non-B) = P (B, non-A) then P(A) = P(B) and also P(A|B) = P(B|A).
