You should supply more information.
If actually weighing the plates is impractical, you could try hanging the plates from a spring, and testing to find the spring's k value, and recording the displacement of the object while hanging from the spring, and use that to calculate the force on the plate, which equals mg. if the density is known, you could immerse the plates in something to find their volume and then calculate their weight from that. or, you could try and pull them with a force meter, taking two data points so that you can solve for the both the friction coefficient and weight.
How do you find dia meter of shaft when bearing no is given?
Almost everywhere!!!
Hello, did you ever find the solution manual for this book? please email me wanted_os@hotmail.com
All you have to do is fine a simple task to do and find simple machines and connect them together to make it. All you have to do is fine a simple task to do and find simple machines and connect them together to make it.
No.
you have to do the arcsin which is sin-1 on your calculator. i have not met anyone in my life who can do sin or arcsin in their head. not even my college teachers. your theta is equal to 20degrees
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
2 sin (Θ) + 1 = 0sin (Θ) = -1/2Θ = 210°Θ = 330°
tan(theta) = 1 then theta = tan-1(1) + n*pi where n is an integer = pi/4 + n*pi or pi*(1/4 + n) Within the given range, this gives theta = pi/4 and 5*pi/4
-0.5736
The answer depends on what theta represents!
1.25
tan theta = sqrt(2)/2 = 1/sqrt(2).
2 sin(x) + 1 = 0 2 sin(x) = -1 sin(x) = -1/2 x = 210° and 330°
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.