To find any term of a geometric sequence from another one you need the common ration between terms: t{n} = t{n-1} × r = t{1} × r^(n-1) where t{1} is the first term and n is the required term. It depends what was given in the geometric sequence ABOVE which you have not provided us. I suspect that along with the 10th term, some other term (t{k}) was given; in this case the common difference can be found: t{10} = 1536 = t{1} × r^9 t{k} = t{1} × r^(k-2) → t{10} ÷ t{k} = (t{1} × r^9) ÷ (t{1} × r^(k-1)) → t{10} ÷ t{k} = r^(10-k) → r = (t{10} ÷ t{k})^(1/(10-k)) Plugging in the values of t{10} (=1536), t{k} and {k} (the other given term (t{k}) and its term number (k) will give you the common ratio, from which you can then calculate the 11th term: t{11} = t(1) × r^9 = t{10} × r
get off the computer and do your work.
P=q/r* * * * *The correct answer is P = k*q/r where k is the constant of proportionality.
Well, honey, if we follow the order given, it goes like this: J, H, R, G, and K. So, the second boy in line would be H. But hey, if those boys are causing this much confusion climbing a hill, maybe they should consider taking up a different hobby!
Suppose N is a perfect number. Then N cannot be a square number and so N has an even number of factors.Suppose the factors are f(1) =1, f(2), f(3), ... , f(k-1), f(k)=N.Furthermore f(r) * f(k+1-r) = N for r = 1, 2, ... k so that f(r) = N/f(k+1-r)which implies that 1/f(r) = f(k+1-r)/NThen 1/f(1) + 1/(f(2) + ... + 1/f(k)= f(k)/N + f(k-1)/N + ... + f(1)/N= [f(k) + f(k-1) + ... + f(1)] / N= 2N/N since, by definition, [f(k) + f(k-1) + ... + f(1)] = 2N
Most organisms lie on a continuum between r-strategists and K-strategists, and the octopus is one of those. The octopus lays a lot of eggs, typical of an r-strategist, but also invests parental care into its offspring, typical of a K-strategist.
no it is a k-strategist
Flamingos are K-strategists
R-strategist species have many offspring with little parental care, while K-strategist species have fewer offspring with more parental care.
Bees are not R-strategist. Bees are considered to be K-strategist because they live in stable environments and produce few offspring.
k-Strategist but act like r-Strategists in many such as expansion.
A K strategist or K species are animals with few, and often large offspring. The nurture and protect their young, reproduce later in life, live long, and population size is stable and near carrying capacity. Examples are elephants, humans, etc... A R strategist is something like insects and weeds.
only retards ask that question you as.
R- Selected species have high population densities while k-selected species have lower population densities
R-strategist species typically have high reproductive rates, short lifespans, and produce many offspring with little parental care. They prioritize quantity over quality in reproduction. In contrast, k-strategist species have lower reproductive rates, longer lifespans, and invest more time and resources in raising fewer offspring with higher chances of survival. They prioritize quality over quantity in reproduction.
The difference is a t, e, c, k, r, and an h.
no a whale is not. Humans are though