Multiply the total weight of the object in grams by 0.03215. Then multiple that result by the Karat weight of the item (14 in your example), and divide that total by 24.
Example:
10 gram 14K ring x .03215 = .32 troy ounces total weight, x 14/24 = .19 troy ounces of gold
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300kg of gold is 803.8 troy pounds or 9,645 troy ounces.
$53,000
24-karat gold is at least 99.9% pure gold, so 1 troy ounce of 24K gold should have at least 0.999 troy ounces (31.072 grams) of gold. (Note that the troy ounce, used for precious metals, is slightly larger than the avoirdupois ounce, used for most ordinary measurements. However, a troy pound is 12 troy ounces, instead of 16 ounces as with an avoirdupois pound.)
I read somewhere that it takes about 1.77 or 1.74 ounces troy of 14k gold to make(smelter) out 1 ounce (troy) of 24k gold. I am trying to find the web site where I read that.. To get 10oz troy of 24k you would need around 17.4 to 17.7 oz troy of 14k
For normal avoirdupois weight, 8 oz is half a pound. For troy ounces, to measure precious metals like gold, there are 14 troy oz per poung.