That depends on how deep the sand is.
4
Square feet is an area and pounds are a weight. There is no direct conversion between the two.
To find the weight of the water inside the wet sand, we first need to calculate the weight of the wet sand delivered: 135 cubic feet * 120 lbs/cubic foot = 16,200 lbs of wet sand. Next, we find the weight of the dry sand in the wet sand delivered: 135 cubic feet * 100 lbs/cubic foot = 13,500 lbs of dry sand. The weight of the water inside the wet sand is the the difference between the weight of the wet sand and the weight of the dry sand: 16,200 lbs (wet sand) - 13,500 lbs (dry sand) = 2,700 lbs of water.
The area that 40 pounds of sand will cover at a depth of 1 inch can be estimated based on the density of sand, which is typically around 100 pounds per cubic foot. Since 40 pounds of sand is about 0.4 cubic feet, and 1 inch is ( \frac{1}{12} ) of a foot, the area covered would be approximately 4.8 square feet. Therefore, 40 pounds of sand will cover roughly 4.8 square feet at a depth of 1 inch.
For 600 square feet, 2 pounds of fertilizer is needed. To find out how many pounds are needed for 900 square feet, calculate the ratio: 2 pounds / 600 square feet = x pounds / 900 square feet. Cross-multiply to find x, the pounds of fertilizer needed for 900 square feet.
The answer will depend on the units for 2. Whether it is 2 inches, feet or something else. Assuming you mean feet, a 12 foot x 12 foot x 2 foot area contains 288 cubic feet. Sand is usually measured in lbs. One cubic foot of sand weighs about 100 lbs (see related questions below). 288 x 100 lbs = 28800 lbs. This is 14.4 tons of sand.
5000 lbs of sand, give or take a hundred.
At 100 lbs per cu ft, that's 2500 pounds. At 2000 lbs/ton, that's 2500/2000 = 1.25 tons
Depends on the type of sand also if it is wet or dry
1 cubic foot=100 lbs of sand 1728 cubic in.=100 lbs of sand 864 cubic in.= 50 lbs of sand 432 cubic in.= 25 lbs of sand and so on and so on
One inch = 1/12 foot 1500 x 1/12 = 125 cubic feet sand weighs 100 pounds /cu ft weight = 100 x 125 = 12500 pounds at 2000 lbs/ton that is 12500/2000 = 6.25 tons
The answer depends on the grain size, lithology, moisture content, and level of compaction of the sand. Generally, one cubic ft of clean (no silt/clay), dry, fine to medium sand that has been compacted to a dense, non-yielding condition will weigh about 110 lbs., while a loose fine to medium sand will weigh about 100 lbs. per cubic foot.