Try them out yourself and make your own judgement. What might be good for someone might be awful for someone else.
A 120 volt table lamp with a 75 watt bulb will pull 0.625 amps. With a 100 watt bulb it will pull 0.833 amps. And with a modern fluorescent 13 watt bulb it will pull 0.108 amps.
amps require lots of breathing room, and some high watt/amp units have fans along with the normal ribbed heat sink cases...thats why amps have those fins..to dissipate heat.. :)
here is Speakers > Mosfed > 15 inch 300 watt. 2500 watt behringer euro. 4 box. 2x2. 18 inch 600 watt. 4500 watt - 1 soundstanderd. 4 w-bin, 1x1. 4 tweuter 250 watt ahuja empli. Destributar + Crossover Behringer super x pro cx2310. + mixer StudioMaster + Computer. Please Crossover Cannection. Repley me...........
here is Speakers > Mosfed > 15 inch 300 watt. 2500 watt behringer euro. 4 box. 2x2. 18 inch 600 watt. 4500 watt - 1 soundstanderd. 4 w-bin, 1x1. 4 tweuter 250 watt ahuja empli. Destributar + Crossover Behringer super x pro cx2310. + mixer StudioMaster + Computer. Please Crossover Cannection. Repley me...........
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
Rockford Fosgate offers a great selection of 900 watt amps. You can also check reviews on the Kenwood 900 watt mono channel amp.
A 1450 watt coffee maker will use around 13 amps at 110 volts.
To find the amperage of a 750-watt heater operating at 120 volts, you can use the formula: Amps = Watts / Volts. Therefore, 750 watts divided by 120 volts equals 6.25 amps. So, a 750-watt heater uses approximately 6.25 amps.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
Watt volts is not an electrical term. Watts are the product of amps times volts.
Yes, a 1200 watt amp can provide good bass for 2 Kicker CVR 12-inch subwoofers. Make sure to set the amp gain correctly, match the impedance of the subwoofers with the amp, and use a proper enclosure for optimal performance.
amps equals watts divided by volts.