depends on the depth of coverage, be more specific.
The area that 60lbs of sand will cover is dependant on how deep you want it.æ One hundred pounds of sand equal 1 cubic foot.Your customer service rep at your local storeæcan calculate how much you will need.
11,923,200 sq in. of sand.
The area that 1 pound of sand can cover depends on the depth of the layer being considered. Typically, 1 pound of dry sand can cover approximately 0.5 to 1 square foot at a depth of about 1 inch. If the depth is increased, the coverage area will decrease accordingly. Therefore, for specific applications, it's important to calculate based on the desired thickness of the sand layer.
use a known volume container to measure a quantity = 200 x (the depth you want the sand).
you would need 3 qb. yards of sand to cover that area L X W X .25 FOR 4 INCHES DIVIDED BY 27
The area that 40 pounds of sand will cover at a depth of 1 inch can be estimated based on the density of sand, which is typically around 100 pounds per cubic foot. Since 40 pounds of sand is about 0.4 cubic feet, and 1 inch is ( \frac{1}{12} ) of a foot, the area covered would be approximately 4.8 square feet. Therefore, 40 pounds of sand will cover roughly 4.8 square feet at a depth of 1 inch.
1 cubic foot=100 lbs of sand 1728 cubic in.=100 lbs of sand 864 cubic in.= 50 lbs of sand 432 cubic in.= 25 lbs of sand and so on and so on
This is a volume calculation. I assume the dimension for the "6" is inches? If so, the volume= 20x20x0.5= 200 cubic ft.= 7.4 cubic yards
To calculate the volume of sand needed to cover an 8x16 area at 1 inch thick, first convert the dimensions to feet: 8 feet by 16 feet. The area is 128 square feet. Since 1 inch is 1/12 of a foot, the volume of sand required is 128 square feet multiplied by 1/12 foot, which equals approximately 10.67 cubic feet of sand.
630 cubic inches
50 pounds covers 0.5 cubic feet. Since the depth is 3 inches, or 1/4 foot, you can cover 0.5/.25 = 2 square feet of area. That is not very much.
Four cubic yards will do it. You theoretically need only 3.7, but that assumes the area you're putting the sand in is perfectly level, flat and low-spot-free...and they never are.