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Separate the balls in 3 separate groups of 3 balls each. Get two groups of 3 and place it on either side of the balance.

If the balance is the same then the probability is that the heavy ball is in the other group off the balance. Or if the ball

was on the group in the balance it would be noticed right away also.

After recognizing the heavier group, you take 2 balls from the remaining group and you weight them, if it's the same,

then the remaining ball must be the heavier one, if not then you would automatically see it in the scale.

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Q: How do you solve the nine ball riddle?
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