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A 10 kg rock is pushed off the edge of a bridge 50 meters above the groundWhat was the kinetic energy of the rock at the midway point of its fall?
Wiki User
∙ 13y ago
zero
Kathlyn Feil
Wiki User
∙ 14y agoIn order to calculate the answer we require the velocity of the mass as it hits the water.
This can be found using the simple equations of motion where we have a constant acceleration.
As such we can use:
V2 = U2 + 2AS
Where:
V = Final velocity (m/s)
U = Initial Velocity (m/s)
A = Acceleration (m/s/s)
S = Distance (m)
The initial velocity is 0, the acceleration is due to gravity (9.81 ms-2) and the distance equals 25m.
As such:
V2 = 02 + (2 x 9.81 x 25)
V2 = 0 + (490.5)
V = Sqrt(490.5)
V = 22.15 m/s
Kinetic energy (EK):
EK = 1/2MV2
(0.5x12) x 22.152
Kinetic Energy = 2,940 joules
Wiki User
∙ 7y agoThe potential energy is mgh where m = 12kg, g = 9.814 m/s/s and h = 25 m. Kinetic energy = potential energy = (12)(9.814)(25) = 2944 joules
Wiki User
∙ 14y ago2,450 joules
Wiki User
∙ 7y agoIt is approx 2900 Joules.
Wiki User
∙ 14y ago2,940
Wiki User
∙ 14y agozero
Wiki User
∙ 13y ago2450
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A 5kg object is being lifted to a height of 8 meters and is dropped what is the kinetic energy of the object at 2 m?
After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.
A 10 kg rock is pushed off the edge of a bridge 50 meters above the ground. what was the kinetic energy of rock befor it began to fall?
zero
A 10 kg rock is pushed off the edge of a bridge 50 meters above the ground. What was the kinetic energy of the rock at the midway point of its fall?
2450
What is the energy of a system by virtue of its motion?
That's called kinetic energy. The formula is: Kinetic energy = (1/2) x mass x velocity2. If mass is in kilograms, and velocity (or speed, really) in meters per second, the energy will be in Joules.
A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground What was the potential energy of the rock before it began to fall?
Kinetic Energy = 1/2 x Mass x Velocity2 As the velocity while the rock is on the bridge's edge is 0, it does not have any kinetic energy: Therefore the answer is zero.
A 5kg object is being lifted to a height of 8 meters and is dropped what is the kinetic energy of the object at 2 m?
After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.
A 10 kg rock is pushed off the edge of a bridge 50 meters above the ground. What was the kinetic energy of the rock at the midway point of its fall?
2450
A 10 kg rock is pushed off the edge of a bridge 50 meters above the ground. what was the kinetic energy of rock befor it began to fall?
zero
What is the mathmetical formula for kinetic energy?
Kinetic Energy = 1/2(mass in kilograms)(meters per second)2
A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground What was the potential energy of the rock before it began to fall?
Kinetic Energy = 1/2 x Mass x Velocity2 As the velocity while the rock is on the bridge's edge is 0, it does not have any kinetic energy: Therefore the answer is zero.
What is the energy of a system by virtue of its motion?
That's called kinetic energy. The formula is: Kinetic energy = (1/2) x mass x velocity2. If mass is in kilograms, and velocity (or speed, really) in meters per second, the energy will be in Joules.
A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground. What was the kinetic energy of the rock at the midway point of its fall?
2,450 joules
Is touching a kinetic energy?
Kinetic energy is the energy of motion. Your touching finger has mass and is moving some meters per second, so that motion is kenetic energy.
What are the factors in kinetic energy?
Kinetic energy = 1/2 x mass x velocity2. Mass in Kg, velocity in meters/sec, energy in Joules
What will be the kinetic energy and velocity of object of mass 62kg?
Its kinetic energy (in joules) will be (31) times (its velocity in meters per second)2 .
Is kinetic energy the same as static energy?
No, Potential Energy is the energy of an object that has the potential to move while kinetic energy is the energy of an object at motion. Potential energy is defined by Mass * Gravity(9.81ms-2) * height(In meters) Kinetic energy is defined by (1/2)*Mass*Velocity2
If you have a 2kg pendulum bob that is 6 meters above the ground at its high point and 1 meter at its low point how can you figure the kinetic energy?
Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.
