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A 10 kg object is lifted up 10 meters How much potential energy has the object gained?
The potential energy gained by lifting a 10 kg object up 10 meters can be calculated using the formula: Potential Energy = mass x gravity x height. In this case, the potential energy gained would be 10 kg x 9.8 m/s^2 x 10 m = 980 Joules. This means that the object has gained 980 Joules of potential energy as a result of being lifted 10 meters above the ground.
How many joules of potential energy does a 1-N book gain when it is elevated 4 m?
The potential energy gained by the book can be calculated using the formula: potential energy = mass * gravity * height. The mass of the book is needed to calculate the exact amount of potential energy gained. Assuming a mass of 1 kg, the potential energy gained would be approximately 39.2 J.
Can you design two physics problems that involve calculating work and gravitational potential energy?
Here are two physics problems involving work and gravitational potential energy: Problem 1: A 5 kg box is lifted 2 meters vertically against gravity. Calculate the work done in lifting the box and the change in gravitational potential energy. Problem 2: A 10 kg object is pushed horizontally across a frictionless surface for a distance of 5 meters. Calculate the work done in pushing the object and the change in gravitational potential energy if the object is then lifted 3 meters vertically.
How do objects acquire potential energy?
For an object to require potential energy a force must be acting on it in a certain direction. Even though the object doesnt move doesnt mean it has potential energy. The most common force of otential energy is Gravity. When an object is lifted off the ground gravity becomes stronger. For a formula of proof then use E=FxD (Energy=Force applied x Distance travelled). If a ball has been lifted by 10 Meters with a force of 500 Newtons then it has a Potential Energy of 5000 Newton Meters,
A 5kg object is being lifted to a height of 8 meters and is dropped what is the kinetic energy of the object at 2 m?
After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.
A 10 kg object is lifted up 10 meters How much potential energy has the object gained?
The potential energy gained by lifting a 10 kg object up 10 meters can be calculated using the formula: Potential Energy = mass x gravity x height. In this case, the potential energy gained would be 10 kg x 9.8 m/s^2 x 10 m = 980 Joules. This means that the object has gained 980 Joules of potential energy as a result of being lifted 10 meters above the ground.
How many joules of potential energy does a 1-N book gain when it is elevated 4 m?
The potential energy gained by the book can be calculated using the formula: potential energy = mass * gravity * height. The mass of the book is needed to calculate the exact amount of potential energy gained. Assuming a mass of 1 kg, the potential energy gained would be approximately 39.2 J.
Can you design two physics problems that involve calculating work and gravitational potential energy?
Here are two physics problems involving work and gravitational potential energy: Problem 1: A 5 kg box is lifted 2 meters vertically against gravity. Calculate the work done in lifting the box and the change in gravitational potential energy. Problem 2: A 10 kg object is pushed horizontally across a frictionless surface for a distance of 5 meters. Calculate the work done in pushing the object and the change in gravitational potential energy if the object is then lifted 3 meters vertically.
1-kg brick is lifted to a height of 30 meters and then dropped How much potential energy remains after 2 seconds of freefall?
Use one of the formulas for constant acceleration to calculate how many meters the brick will fall after 2 seconds. Subtract this from the 30 meters, to see how high the brick is above ground. Finally, use the formula for potential energy: PE = mgh, to calculate the potential energy.
What is the potential energy of a crate lifted with a force of 100 newtons a vertical distance of 2 meters?
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
How do objects acquire potential energy?
For an object to require potential energy a force must be acting on it in a certain direction. Even though the object doesnt move doesnt mean it has potential energy. The most common force of otential energy is Gravity. When an object is lifted off the ground gravity becomes stronger. For a formula of proof then use E=FxD (Energy=Force applied x Distance travelled). If a ball has been lifted by 10 Meters with a force of 500 Newtons then it has a Potential Energy of 5000 Newton Meters,
A 5kg object is being lifted to a height of 8 meters and is dropped what is the kinetic energy of the object at 2 m?
After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.
A bob of mass of 0.18 kilograms is released from a height of 45 meters above the ground level. What is the value of the kinetic energy gained by the bob at the ground level?
The kinetic energy gained by the bob at ground level can be calculated using the principle of conservation of energy. The potential energy at the initial height is converted into kinetic energy at ground level. Thus, the kinetic energy gained by the bob at ground level is equal to the initial potential energy, which is calculated as mgh, where m is the mass of the bob (0.18 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (45 meters). Substituting these values, we find the kinetic energy gained to be 79.38 Joules.
How many joules of 20 kg box is lifted 5 meters?
The potential energy gained by lifting a 20 kg box 5 meters is calculated using the formula PE = mgh, where m is mass, g is acceleration due to gravity, and h is height. Plugging in the values, we get PE = 20 kg * 9.81 m/s^2 * 5 m = 981 J. So, 981 Joules of energy is required to lift a 20 kg box 5 meters.
How a 100 kg crate is lifted to a height of 10 meters. At this height what is the potential energy of the crate?
The potential energy of the crate at a height of 10 meters is given by the formula PE = mgh, where m is the mass (100 kg), g is the acceleration due to gravity (9.81 m/s²), and h is the height (10 meters). Substituting the values, we get PE = 100 kg * 9.81 m/s² * 10 meters = 9810 Joules.
Which gains more gravitational potential energy a 4 N object lifted 3.0 m or a 5 N object lifted 2.0 m?
Let's see. First.....,F = mam = F/am = 4 N/9.8 m/s2= 0.408 kilograms----------------------m = 5 N/9.8 m/s2= 0.510 kilograms-----------------------------secondly......,PE = mghPE = (0.408 kg)(9.8 m/s2)(3.0 meters)= 11.99 Joules==============A 4 Newton object lifted 3 meters gains more potential energy.
A 100 kg crate is lifted to a height of 10 meters. At this height what is the potential energy of the crate?
The potential energy of the crate at a height of 10 meters can be calculated using the formula PE = mgh, where m is the mass (100 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (10 m). Therefore, the potential energy of the crate at 10 meters height is PE = 100 kg * 9.8 m/s^2 * 10 m = 9800 J.
