4.29 m/s2
The extra tension depends not on the velocity of the elevator, but on its acceleration.
No, the force in tension of a string is not conservative. The only non-conservative force acting is the tension force, but it acts perpendicular to the path of the object at every instant, and so it does zero work.
Tension in the rope needed to pull the object of mass 100 kg with an acceleration of 1 m/s^2 is 100 N. Since the force is the product of mass and acceleration. So 100 x 1.0 = 100 NWith this force of 100 N the body is moved through a distance of 5.0 m and hence work done will be 500 joule. Since the formula for the work done is F s cos @Here F = 100 N ; s = 5.0 m ; @ = 0 as tension and the displacement in the same direction. Hence the value of work done is 500 joule.
If the object hangs from a weightless string or thread, the tension in the thread is equal to the weight of the object. If there is weight distributed all the way from the ceiling to the bottom of whatever is hanging, then the tension at every point is equal to the weight of everything below that point.
F=m*(g+a)=1600*(9.8+.7)=16800N
i think that acceleration is directly proportional to surface tension.....
The extra tension depends not on the velocity of the elevator, but on its acceleration.
Tension = mass(acceleration) + force of gravity Force of gravity equals mass times gravity (9.8m/s2)
Unless the train is in a curve, you cannot have constant speed and constant acceleration. You either have constant speed and zero acceleration, or you have changing speed and constant acceleration. Please restate the question.
Tension in the rope needed to pull the object of mass 100 kg with an acceleration of 1 m/s^2 is 100 N. Since the force is the product of mass and acceleration. So 100 x 1.0 = 100 NWith this force of 100 N the body is moved through a distance of 5.0 m and hence work done will be 500 joule. Since the formula for the work done is F s cos @Here F = 100 N ; s = 5.0 m ; @ = 0 as tension and the displacement in the same direction. Hence the value of work done is 500 joule.
No, the force in tension of a string is not conservative. The only non-conservative force acting is the tension force, but it acts perpendicular to the path of the object at every instant, and so it does zero work.
Yes
If the object hangs from a weightless string or thread, the tension in the thread is equal to the weight of the object. If there is weight distributed all the way from the ceiling to the bottom of whatever is hanging, then the tension at every point is equal to the weight of everything below that point.
if the angle is 90 degrees, 5 x 9,8 = T
F=m*(g+a)=1600*(9.8+.7)=16800N
I think its depends on the nature of the liquid, the surrounding environment like (Gravitational acceleration ) and temperature
For simplicity let us assume the acceleration due to gravity to be 10 m/s2 The max force on the string is be 700 N. ie with mass of 40 kg, the acceleration max has be 700/40 ie 35/2 m/s2 The g value is 10 so the excess acceleration that is getting added is 35/2 -10 ie 15/2 m/s2. This acceleration is due to the acceleration of the ascending lift. Hence the tension on the lift cable will be got by the product of the mass of the lift and its acceleration. So it comes to be 1500 N. Already a tension which equals to the weight of the lift namely 2000 N is there. Hence the total tension becomes 3500N. I can't understand why the ans seems equal to 4200 N and 440 N as you have mentioned in the problem.