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A 20 kg box is lifted to a 4.0 m shelf if it falls what is its velocity as it reaches the floor?
if: v = final velocity, u = initial velocity, a = acceleration, s = distance
then: v2 = u2 + 2as
This is just one of the different formulae you could choose to use, but the advantage of this one is that you don't have to calculate time taken before the calculation can be done. The mass of the box (20kg) is not needed, as all objects will accelerate at the same rate unless wind resistance is significant. Unless the box has a parachute or very large surface area, this shouldn't be a complication.
u = 0
a = 9.8 ms-2 (acceleration due to gravity)
s = 4 m
v2 = 02 + 2*(9.8 ms-2)*(4 m)
v2 = 78.4 (ms-1)2
v = sqrt(78.4) ms-1
v = 8.9 ms-1
What else can I help you with?
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