parameters given are :
mass(m)=20kg
height(h)=30m
acceleration due to gravity(g)=9.8m/s squared
But K.E=1/2MV`2 = mgh = 20x9.8x30 =5880 joules or 5.88 kilo-joules.
The kinetic energy of an object is given as .5mv2, where m is the mass of the object, and v is the velocity of the object. So in this case, we can't determine the kinetic energy directly, but we can determine the potential energy, which is given by mgh, where m is the mass, g is the gravitaional constant, and h is the height above the ground that the object falls from. We know that all of the potential energy is going to be converted into kinetic energy. So mgh = .5mv2. (20 kg)(9.8 m/s2)(30 m)= 5880J
parameters given are :
mass(m)=20kg
height(h)=30m
acceleration due to gravity(g)=9.8m/s squared
But K.E=1/2MV`2 = mgh = 20x9.8x30 =5880 joules or 5.88 kilo-joules.
vf2=vi2+2ad
Ek=1/2mv2
vf**2=0+2(9.81m/s**2)(30)
vf**2=588.6
Ek=0.5*20*588.6
Ek=5886 joules
. . . at 22.7m/s
9m/s
IKE = ½mv² = ½ × 20 kg × (2.8 m/s)² = 78.4 kgm²/s² = 78.4 J.
Kinetic energyThe formula for kinetic energy, Ek, could not be simpler.Ek = (1/2)mv2, where m is mass (in kg) and v is velocity (in m s-1). If you prefer, you could write Ek = mv2/2.or, 810j=1/2*20Kg*v2or,v2=810j*2/20Kgor,v=sqrt of 81so,v=9m s-1
The reverse is usually done .... Define temperature in terms of KE. The temperature of a body is proportional the the average Kinetic Energy of the particles (molecules or atoms) that make up the body. Can't be done the other way because a car traveling at 60 miles per hour has Kinetic energy which has nothing to do with temperature. The car doesn't care if is 100 degrees or 20 degrees.
Doubling mass affects kinetic energy in that the greater the mass, the greater the kinetic energy. OK, but if you have a 10kg mass traveling at 2m/s and it bumps into and sticks to a 10g mass, the resultant speed would be 1m/s. The momentum stays the same. KE before is 10*2*2/2= 20, while the KE after is 20*1*1/2= 10. So it is not that the above answer is wrong, but rather, you question is not clear.
The relation between kinetic energy is proportional to the square of velocity. Momentum is directly proportional to velocity. If the momentum of an object is doubled, but its mass does not increase (so velocity remains well below the speed of light), then its velocity is doubled. If the velocity is doubled then the kinetic energy increases by the square of 2, or four time.
The object's kinetic energy is 78.4 joules.
A. 56 j
6,000 J
To get the kinetic energy of an object you need both mass and velocity. As it stands it can't be answered, as "mm" isn't a recognized unit of velocity
78.4 joules at 2.8m/s
Kinetic Energy = 1/2 m V2 = 1/2 (20) (2.8)2 = 78.4 joules
KE=(1/2)mv246080 Joules
IKE = ½mv² = ½ × 20 kg × (2.8 m/s)² = 78.4 kgm²/s² = 78.4 J.
If at the top of the swing the pendulum is STOPPED then it has zero kinetic energy.
I know this isn't technically 'correct', but the answer for this penn foster question that will make you get a 'correct' to pop up, is strangely A.
Kinetic energyThe formula for kinetic energy, Ek, could not be simpler.Ek = (1/2)mv2, where m is mass (in kg) and v is velocity (in m s-1). If you prefer, you could write Ek = mv2/2.or, 810j=1/2*20Kg*v2or,v2=810j*2/20Kgor,v=sqrt of 81so,v=9m s-1
KE = 1/2 M V2 = 1/2 (20) (2.8)2 = 78.4 joules