Assuming that all the energy dissipated by kinetic friction goes into melting a small mass m of the ice, and that the rest of the ice block remains at -1.5°C, determine the value of m.
coefficient kinetic
Ukn
static usully greater then kinetic
The coefficient of kinetic energy is a constant for friction acting as a retarding or dissipative force to calculate the total force on the object. The coefficient of friction u is represented in equation by the relation F = u*N, where N is the normal force.
When objects are at rest on each other (i.e. static friction) their microscopic irregularities can settle into each other - and can also form electrostatic bonds.
The coefficient of static friction is always larger because it takes more initial force to move an object that is at rest.
.419 .419
The coefficient of kinetic friction between wool felt and aluminum is about 0.24 to 0.26.
coefficient kinetic
Ukn
static usully greater then kinetic
static friction= normal contact force*coefficient of static friction 40 = (600*9.8) * CSF CSF=40/(600*9.8) (you can calculate that yourself, i cant be bothered) there isn't enough info to work out the coefficient of kinetic friction
The coefficient of static or kinetic friction depends on the surfaces that are causing friction. The formula for it is: force of friction over normal force.
0.35, approximately
The coefficient of kinetic energy is a constant for friction acting as a retarding or dissipative force to calculate the total force on the object. The coefficient of friction u is represented in equation by the relation F = u*N, where N is the normal force.
static friction is higher in most cases, if you're talking about the coefficient of static or kinetic friction
No, coefficient of friction is dependent on the materials in contact, not their mass. However the FORCE of friction will increase as the mass increases in this case.