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A 5.0gram sample of gold and a 5.0gram sample of iron both absorb exactly 25 calories of energy The specific heat of gold is 0.03 cal over gC The specific heat of iron is 0.11 cal over gC?
Wiki User
∙ 13y ago
The query is incomplete. So it has to be: What will be the rise in temperature in both?
Let us use the formula Q = m s t.
As m remains constant and Q too remains constant then st, the product must be a constant. Hence s and t are inversely related.
Higher the value of s then less the rise in temperature.
For gold its value will be t = Q/m * 1/s = 5/0.03 = 500/3 degree rise ie 167 degree nearly
For iron the value will be t = 5/0.11 = 500/11 = 45.5 degree nearly
Wiki User
∙ 13y ago
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