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A 8000 kg engine pulls a train of 5 wagons each of 2000 kg along a horizontal track if the engine exerts a force of 40000N and the track offers friction force of 5000N then calculate 1 the net acclera?
Wiki User
∙ 11y ago
Ans. :- net acceleration = 40000 - 5000 = 35000 N.
Wiki User
∙ 11y ago
Anonymous
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If object has a volume of 4.0m3 and weighs 40000 N What will its weight be in water?
40000N/9.81m/s^2=4077kg density of object = 4077kg/4m^3=1019.25kg/m^3 density of water = 1000kg/m^3 So it will sink! Water displace = 4*1000=4000kg (4077-4000)*9.81 = 755N D
What is a real life experience in which forces change the speed and direction of an object?
Imagine a 1000kg car going down a road at 40 m/s. A dog jumps out in front of the car and the driver slams on the brakes. The required force to stop the car is 40000N. Now the force of the brakes acting on the tires will cause the car to shudder and move side to side. Another example: I am jogging(100kg) at 6m/s in a straight line. My friend (150kg) tackles me from the side at 5 m/s. He is applying 750N of force on me and will quite drastically change my direction. And yet another example: A log is floating north down a stream. You throw a 1kg rock at the log at 15 m/s. The rock will apply 15N of force on the log. Now I am going to discount the water for the sake of the problem because that is advanced physics. Say the 5 kg log is moving straight ahead and 5 m/s. It has 25N of force in the north direction(+,+). the rock you threw directly behind the log will hit with 15N of force. Discounting any sort of air resistance or other Non-conservative force that would detract from the force you are applying, the log is now moving north at 8m/s. Take the force from the rock and add it to the force of the log and you get 40N. Divide that by the weight of the log (5kg) and you get the new speed. Once again, I didn't include several factors that would happen in the real world, but that is the general idea.
