The formula for position is x = 1/2at2.
If we start at a distance of 40 feet, and gravity is 32 feet per second squared.
So in this instance:
40 = 1/2 (32) t2
40 = 16 t2
40/16 = t2
2.5 = t2
t = 1.58 seconds
No, work is not done when a ball is dropped from a window to the ground because work is only done when a force is applied over a distance. In this case, gravity is the force pulling the ball down, and there is no force acting against it over a distance.
After each bounce, the ball reaches half of the height from which it was dropped. Since the ball was initially dropped from 10 feet, on the first bounce it will reach 5 feet, on the second bounce it will reach 2.5 feet, on the third bounce it will reach 1.25 feet, and on the fourth bounce it will reach 0.625 feet.
When a ball is dropped, the energy involved is primarily gravitational potential energy being converted into kinetic energy as the ball accelerates towards the ground. When the ball hits the ground, some of this kinetic energy is transferred to the ground as impact energy.
The time it takes for a ball to reach the ground depends on the height from which it is dropped and the acceleration due to gravity. Without knowing these specific values, a general calculation cannot be provided.
The ball will take approximately 1.74 seconds to reach the ground. This can be calculated using the equation ( t = \sqrt{\frac{2h}{g}} ), where ( h = 12.0 , m ) and ( g = 9.81 , m/s^2 ).
No, work is not done when a ball is dropped from a window to the ground because work is only done when a force is applied over a distance. In this case, gravity is the force pulling the ball down, and there is no force acting against it over a distance.
Yes... Its not the weight but the force of gravity
After each bounce, the ball reaches half of the height from which it was dropped. Since the ball was initially dropped from 10 feet, on the first bounce it will reach 5 feet, on the second bounce it will reach 2.5 feet, on the third bounce it will reach 1.25 feet, and on the fourth bounce it will reach 0.625 feet.
When a ball is dropped, the energy involved is primarily gravitational potential energy being converted into kinetic energy as the ball accelerates towards the ground. When the ball hits the ground, some of this kinetic energy is transferred to the ground as impact energy.
The time it takes for a ball to reach the ground depends on the height from which it is dropped and the acceleration due to gravity. Without knowing these specific values, a general calculation cannot be provided.
The force that pulls a ball to the ground after being dropped is gravity. Gravity is the natural force of attraction between two objects with mass, in this case, the ball and the Earth.
The ball will take approximately 1.74 seconds to reach the ground. This can be calculated using the equation ( t = \sqrt{\frac{2h}{g}} ), where ( h = 12.0 , m ) and ( g = 9.81 , m/s^2 ).
The ball had potential energy before it was dropped. This potential energy was due to its position above the ground.
The ball which you drop from 5 feet will reach the ground first.
3 ft
The key factor in determining the time it takes for objects to fall is the acceleration due to gravity, which is the same for all objects regardless of their mass or material composition. Therefore, both the aluminum and steel balls experience the same acceleration and reach the ground at the same time when dropped from the same height.
A ball bounces when it is dropped because of the force of gravity pulling it down and the elasticity of the ball's material. When the ball hits the ground, some of its energy is transferred into the ground as heat and sound, causing it to eventually come to a stop.