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A ball is thrown horizontally at 20 ms from the top of a cliff 50 meters high How long does it take the ball to reach the ground?
Use the equation [ D = 1/2 g t2 ] .
D = the distance of free-fall = 50 m
g = acceleration of gravity = 9.8 m/sec2
t = time in free-fall
D = 1/2 g t2
2D / g = t2
t = sqrt( 2D / g ) = sqrt( 100 / 9.8 ) = 3.1944 seconds(rounded)
The horizontal velocity that the ball has when it's launched doesn't appear
in the calculation, because it makes absolutely no difference in the result.
Any effects of air resistance have been ignored in arriving at this solution.
What else can I help you with?
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff. How long was the ball in the air3?
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
A ball is thrown horizontally from a cliff at a speed of 15 and strikes the ground 45 meters from the base of the cliff How high was the cliff?
Well, let's think about this together. The horizontal distance the ball travels is 45 meters, and we know the initial horizontal velocity is 15 m/s. Using the formula for horizontal distance, time, and velocity, we can calculate the time it takes for the ball to reach the ground. Then, we can use this time in the vertical motion formula to find the height of the cliff. Remember, mistakes are just happy accidents in the world of math!
A ball is thrown horizontally from a cliff at a speed of 9 meters per second What is its speed one second later?
Ignoring air resistance, its horizontal speed is still 9 meters per second, its vertical speed is approx. 9.81 m/s, as the acceleration of gravity is 9.81 meters per second per second.
What happens when i stand on the edge of a cliff and throw a ball into a canyon?
The ball will follow a parabolic trajectory as it moves through the air, influenced by gravity. Eventually, the ball will hit the ground of the canyon below. It will travel a distance horizontally and vertically before reaching the ground, with the exact path dependent on the initial velocity and angle at which it was thrown.
A ball is thrown horizontally from a cliff at a speed of 8 meters per second. What is its speed one second later?
After a second, the ball will still have a horizontal velocity of 8 meters per second. It will also have a vertical velocity of 9.8 meters per second (Earth's acceleration is about 9.8 meters per square second). The combined speed (using the Law of Pythagoras) is about 12.65 meters per second.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How high was the cliff rounded to the nearest meter?
Answer: 44 meters
A ball is thrown horizontally at 20 meters from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
64 METERSA+
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How fast was the ball thrown?
10 m/s
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How far form the base of the cliff does the ball strike the ground?
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How long was the ball in the air?
Answer: 3 seconds
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How long does it take the ball to reach the ground?
"3.2" or "3.20" please put all of that
A ball thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How high was the cliff?
If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt) It also took 4 secs to travel vertically. It started with a vertical velocity of 0 m/s. Using x=v0 + (1/2) a t2 a = -g ( Acceleration due to gravity 9.8m/s2) x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m It fell 78.4 meters before coming to a stop.
A ball is thrown horizontally at 20 ms from the top of a cliff 50 meters high. How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
A ball is thrown horizontally at 20 from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
A rock is thrown from a cliff and hits the ground 5 seconds later at a distance of 50 meters from the cliff How high was the cliff?
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
What object exhibit two dimensional?
An object thrown upward at an angle An object that's thrown horizontally off a cliff and allowed to fall
