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A ball is thrown horizontally at 20 ms from the top of a cliff 50 meters high How long does it take the ball to reach the ground?
Wiki User
∙ 13y ago
Use the equation [ D = 1/2 g t2 ] .
D = the distance of free-fall = 50 m
g = acceleration of gravity = 9.8 m/sec2
t = time in free-fall
D = 1/2 g t2
2D / g = t2
t = sqrt( 2D / g ) = sqrt( 100 / 9.8 ) = 3.1944 seconds(rounded)
The horizontal velocity that the ball has when it's launched doesn't appear
in the calculation, because it makes absolutely no difference in the result.
Any effects of air resistance have been ignored in arriving at this solution.
Wiki User
∙ 13y ago
Wiki User
∙ 7y agothe time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
Wiki User
∙ 7y agothe time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 seconds
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A ball is thrown horizontally from a cliff at a speed of 9 meters per second What is its speed one second later?
Ignoring air resistance, its horizontal speed is still 9 meters per second, its vertical speed is approx. 9.81 m/s, as the acceleration of gravity is 9.81 meters per second per second.
A ball is thrown horizontally from a cliff at a speed of 8 meters per second. What is its speed one second later?
After a second, the ball will still have a horizontal velocity of 8 meters per second. It will also have a vertical velocity of 9.8 meters per second (Earth's acceleration is about 9.8 meters per square second). The combined speed (using the Law of Pythagoras) is about 12.65 meters per second.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How high was the cliff?
t=(square root of)(2d/g)t=2(78.4)/9.8t=156.8/9.8t=(square root of)16t=4 seconds
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff. How fast was the ball thrown?
If the ball ended 40 m from the cliff after 4 seconds, the original horizontal velocity was 10 m/s. You can calculate the height assuming standard gravity acceleration (g = 9.81 m/s2) and zero original vertical velocity, by calculating the final downward velocity vy2, vy2 = a x t = 9.81 m/s2 x 4 s = 39.24 m/s and from this the average velocity, vav = 39.24 m/s / 2 =19.62 m/s and multiply by 4 s, 19.62 m/s x 4 s = 78.48 m.
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How high was the cliff?
KE before collision =1/2 m v2 = 1/2 m (15)2= 1/2 m 225 (Velocity)2 after collision v2=u2 +2as Final velocity is 0 when object is at maximum height u is the initial velocity just after the rebound a is due to gravity = -9.8ms-2 s is the displacement = 5m 0 = u2 + 2(-9.8)5 u2=98 (ms-1)2 KE after rebound = 1/2 m 98 since mass does not change Fraction of KE remaining = 98/225 Fraction lost 1 - fraction remaining 1- (98/225) = 127/225 Not: if g is taken to be 10ms-2, then fraction is 125/225 = 4/9
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How high was the cliff rounded to the nearest meter?
Answer: 44 meters
A ball is thrown horizontally at 20 meters from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
64 METERSA+
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How fast was the ball thrown?
10 m/s
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How far form the base of the cliff does the ball strike the ground?
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How long was the ball in the air?
Answer: 3 seconds
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How long does it take the ball to reach the ground?
"3.2" or "3.20" please put all of that
A ball thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How high was the cliff?
If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt) It also took 4 secs to travel vertically. It started with a vertical velocity of 0 m/s. Using x=v0 + (1/2) a t2 a = -g ( Acceleration due to gravity 9.8m/s2) x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m It fell 78.4 meters before coming to a stop.
A ball is thrown horizontally at 20 from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
A ball is thrown horizontally at 20 ms from the top of a cliff 50 meters high. How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
A rock is thrown from a cliff and hits the ground 5 seconds later at a distance of 50 meters from the cliff How high was the cliff?
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
What object exhibit two dimensional?
An object thrown upward at an angle An object that's thrown horizontally off a cliff and allowed to fall
