The answer for this question cannot be answered as we do not know how much force was applied to the ball for it to reach this height, alough for that height it would be around 3800 newtons
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
When a basketball is thrown upward, it is acted upon by gravity, which pulls it back down towards the ground. As it moves upward, its velocity decreases until it reaches its peak height and momentarily stops, then gravity causes it to accelerate back downward due to the force of gravity.
The initial velocity of the ball is 16 feet per second when thrown upward. The velocity decreases as the ball travels upward due to gravity until it reaches its peak and starts to fall back down.
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
t matters how much mass the ball has
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
When an object is thrown upward, work is done against gravity as the object moves upward. The amount of work done is equal to the force applied to lift the object multiplied by the distance it moves vertically.
There is no such thing as "interconversion of body" in this case. There are energy conversions; perhaps that's what you mean?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
When a basketball is thrown upward, it is acted upon by gravity, which pulls it back down towards the ground. As it moves upward, its velocity decreases until it reaches its peak height and momentarily stops, then gravity causes it to accelerate back downward due to the force of gravity.
The initial velocity of the ball is 16 feet per second when thrown upward. The velocity decreases as the ball travels upward due to gravity until it reaches its peak and starts to fall back down.
v2 = u2 + 2as where v = current velocity, u = initial velocity, a = acceleration, and s = displacement. Taking a = - 9.8 ms-2 v2 = 182 - (9.8 x 11 x 2) = 108.4 v = 10.4 ms-1
When two identical balls are thrown directly upward, they will follow the same path and reach the same height before falling back down due to gravity.
9.8 m/s (2) Squared
The velocity of a ball thrown upward at W ft/sec will gradually decrease due to gravity until it reaches its highest point (at which the velocity will be 0 ft/sec). After reaching the peak, the ball will then start to fall back down, increasing in velocity until it reaches the ground.