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A bike accelerates uniformly from rest to a speed of 7.10 ms over a distance of 35.4 m Determine the acceleration of the bike?
Wiki User
∙ 12y ago
0.712 m/s^2
Wiki User
∙ 12y ago
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A motorcycle accelerates from 15 ms to 20 ms over a distance of 50 meters. What is its average acceleration?
1.75 m/s^2
To determine the speed of an object divide distance by acceleration?
No, that won't do it. You need to divide the distance the object went by the time it took to go that distance.
What is the dimensional formula of acceleration due to gravity?
An acceleration is a velocity divided by a time, so you have: acceleration = velocity / time acceleration = (distance / time) / time acceleration = distance / time2 The gravitational field can also be expressed as force / mass; this is equivalent to distance / time2.
If a car goes in 6.8 seconds how do you figure out the acceleration?
Acceleration= distance / velocity squared
How is average velocity different from acceleration?
For a start, acceleration doesn't even have the same units as velocity: acceleration is a velocity divided by time, so while speed or velocity have units of [distance]/[time], acceleration has units of [distance]/[time squared]
An object uniformly accelerates over a distance of 100 m in 20 seconds. What is the acceleration?
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
A motorcycle accelerates from 15 ms to 20 ms over a distance of 50 meters. What is its average acceleration?
1.75 m/s^2
If you know the distance traveled and the time traveled can YOU determine an object and ACCELERATION?
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
A car traveling at 15 m s accelerates to 35m s covering distance of 80 meters what was the acceleration rate?
It was 6.25 ms^-2
To determine the speed of an object divide distance by acceleration?
No, that won't do it. You need to divide the distance the object went by the time it took to go that distance.
If a drag racer travels 3 tenths of a mile in 8 seconds what is the rate of acceleration?
It is impossible to determine acceleration simply from time and distance.
What is a speedboat's acceleration if its speed uniformly from twenty meters per second to thirtyone meters per second in a distance of 210 m?
.052 meters per second or .09 per meter
How can you use an object's velocity and the time it takes to travel a certain distance to determine its acceleration?
You would need to sample the velocity at at least two different points of time in order to determine how to velocity is changing. This is because velocity is the first order integral of acceleration, making acceleration the first order differential of velocity. Distance does not really enter into the equation as that is a second order factor, except that you can use distance traveled from one time to the next to estimate velocity
A skater increases her speed uniformly from 2.0 meters per second to 7.0 meters per second over a distance of 12 meters The magnitude of her acceleration as she travels this 12 meters is?
5.0 meters every second.
How do you get the acceleration of an object?
Acceleration= Distance divided by time
What is the dimensional formula of acceleration due to gravity?
An acceleration is a velocity divided by a time, so you have: acceleration = velocity / time acceleration = (distance / time) / time acceleration = distance / time2 The gravitational field can also be expressed as force / mass; this is equivalent to distance / time2.
A 1.20 x 103 kg car accelerates uniformly for 15.0s from rest During this time the car travels 176m north What is the net force acting on the car during this acceleration?
A race car has a mass of 708 kg It starts from rest and travels 35 m in 3.2 s The car is uniformly accelerated during the entire time What net force is applied to it? . Total distance moved = Vi * t + ½ * at^2 It starts from rest Initial velocity = 0 . And travels 35 m Distance = 35 m . in 3.2 s time = 3.2 s . Total distance moved = Vi * t + ½ * at^2 35 = 0 + ½ * a *3.2^2 35 = ½ * a * 10.24 . a = (35 * 2) ÷ 10.24 a = 6.836 m/s^2 . Force = mass * acceleration Mass = 708 kg . Force = 708 * 6.836= Force = 4839.9 N .
