Equations:
F=m*a
d=vi*t+1/2*a*t²
Given Variables
m=.5kg
vi=0m/s
d=8m
t=2s
8=0m/s*2s+1/2*a*2s²
a=4m/s²
F=.5kg*4m/s
F=2N
The acceleration of the box will be 5 m/s^2 (Net force = 25 N - 47 N = -22 N, and a = F/m = -22 N / 4 kg = -5 m/s^2). The tension in the cord will be 47 N (equal to the weight of the box being pulled), and the weight hanging will experience a tension of 25 N on the cord.
Frictional force and tension in a horizontal rope are two common forces that act mostly in a horizontal direction. These forces are important in scenarios involving objects moving along a surface or being pulled horizontally.
If, somehow miraculously, the block is on a frictionless slide, and there isno frictional force opposing its horizontal motion, thenF = M AA = F/M = 583/44 = 13.25 m/s2 = about 1.35 G's
The acceleration of the 7 kg mass being pulled by a 56 N force can be calculated using Newton's second law, which states that force equals mass times acceleration (F = ma). Rearranging the formula, acceleration (a) = force (F) / mass (m). Plugging in the values, we get acceleration = 56 N / 7 kg = 8 m/s^2.
I think so. I'm not a physics expert but see if this makes sense to you.Force = mass * accelerationdouble the mass and you getForce = 2 * mass * accelerationdouble the force with double the mass and you get2 * Force = 2 * mass * accelerationusing simple division math you cancel the 2's which results inForce = mass * accelerationSo I think it would be the same acceleration.
The acceleration of the box will be 5 m/s^2 (Net force = 25 N - 47 N = -22 N, and a = F/m = -22 N / 4 kg = -5 m/s^2). The tension in the cord will be 47 N (equal to the weight of the box being pulled), and the weight hanging will experience a tension of 25 N on the cord.
the force acting down the slope = sin 30 * 25 (kg) = 0.5 * 25 = 12.5 kg = (12.5 * 9.806 ) 122.575 newtons = resultant force of (122.575-120 ) 2.575 newtons downhill giving downhill acceleration of (using f=ma) 0.103 (m/s)/s
The blocks will accelerate together due to the force applied and the absence of friction. The acceleration of the system will depend on the net force acting on it, which is equal to the applied force minus the tension in the strings. The relationship between the masses and the tension in the strings can be determined using Newton's second law.
weight is a function of (mass * acceleration due to gravity) and is a force acting toward the earths centre (vertically down) . if your pulling force is horizontal, then it wont affect the weight
Frictional force and tension in a horizontal rope are two common forces that act mostly in a horizontal direction. These forces are important in scenarios involving objects moving along a surface or being pulled horizontally.
No, but in a sleigh pulled by reindeer.
If, somehow miraculously, the block is on a frictionless slide, and there isno frictional force opposing its horizontal motion, thenF = M AA = F/M = 583/44 = 13.25 m/s2 = about 1.35 G's
The acceleration of the rock can be calculated using Newton's second law, which states that acceleration is equal to the net force divided by the mass of the object. In this case, the acceleration of the 10 kg rock pulled with a net force of 80N would be 8 m/s^2.
F=mass * acceleration 60kg m/s^2=10kg * acceleration 6m/s^2 = acceleration
Santa travels on his sleigh, pulled by reindeer.
F = m aa = F/m = (800) / (1,000) = 0.8 m/sec2
Santa travels in a sleigh pulled by reindeer.