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A 47-N box is pulled along a frictionless horizontal surface by a 25-N weight hanging from a cord on a frictionless pulley?
The acceleration of the box will be 5 m/s^2 (Net force = 25 N - 47 N = -22 N, and a = F/m = -22 N / 4 kg = -5 m/s^2). The tension in the cord will be 47 N (equal to the weight of the box being pulled), and the weight hanging will experience a tension of 25 N on the cord.
Which forces act mostly in a horizontal direction?
Frictional force and tension in a horizontal rope are two common forces that act mostly in a horizontal direction. These forces are important in scenarios involving objects moving along a surface or being pulled horizontally.
What is the acceleration of a 38 kg block of cement when pulled sideways with a net force of 245 N?
If, somehow miraculously, the block is on a frictionless slide, and there isno frictional force opposing its horizontal motion, thenF = M AA = F/M = 583/44 = 13.25 m/s2 = about 1.35 G's
What is the acceleration of a 7 kg mass being pulled by a 56 newton force?
The acceleration of the 7 kg mass being pulled by a 56 N force can be calculated using Newton's second law, which states that force equals mass times acceleration (F = ma). Rearranging the formula, acceleration (a) = force (F) / mass (m). Plugging in the values, we get acceleration = 56 N / 7 kg = 8 m/s^2.
A block has acceleration A when pulled by a string If two identical blocks are glued together and pulled with twice the original force what will their acceleration be?
I think so. I'm not a physics expert but see if this makes sense to you.Force = mass * accelerationdouble the mass and you getForce = 2 * mass * accelerationdouble the force with double the mass and you get2 * Force = 2 * mass * accelerationusing simple division math you cancel the 2's which results inForce = mass * accelerationSo I think it would be the same acceleration.
A 47-N box is pulled along a frictionless horizontal surface by a 25-N weight hanging from a cord on a frictionless pulley?
The acceleration of the box will be 5 m/s^2 (Net force = 25 N - 47 N = -22 N, and a = F/m = -22 N / 4 kg = -5 m/s^2). The tension in the cord will be 47 N (equal to the weight of the box being pulled), and the weight hanging will experience a tension of 25 N on the cord.
What is the acceleration of the 25 kg crate which is pulled by a rope along a frictionless surface at an angle of 30 degrees above the horizontal if the tension on the rope is 120 N?
the force acting down the slope = sin 30 * 25 (kg) = 0.5 * 25 = 12.5 kg = (12.5 * 9.806 ) 122.575 newtons = resultant force of (122.575-120 ) 2.575 newtons downhill giving downhill acceleration of (using f=ma) 0.103 (m/s)/s
Three blocks that are connected by massless strings are pulled along a frictionless surface by a horizontal force?
The blocks will accelerate together due to the force applied and the absence of friction. The acceleration of the system will depend on the net force acting on it, which is equal to the applied force minus the tension in the strings. The relationship between the masses and the tension in the strings can be determined using Newton's second law.
If a person pulled during rest weigh more than when pulled in not rest position?
weight is a function of (mass * acceleration due to gravity) and is a force acting toward the earths centre (vertically down) . if your pulling force is horizontal, then it wont affect the weight
Which forces act mostly in a horizontal direction?
Frictional force and tension in a horizontal rope are two common forces that act mostly in a horizontal direction. These forces are important in scenarios involving objects moving along a surface or being pulled horizontally.
In Finland do santa travels on a swan?
No, but in a sleigh pulled by reindeer.
What is the acceleration of a 38 kg block of cement when pulled sideways with a net force of 245 N?
If, somehow miraculously, the block is on a frictionless slide, and there isno frictional force opposing its horizontal motion, thenF = M AA = F/M = 583/44 = 13.25 m/s2 = about 1.35 G's
What is the acceleration of a 10 kg rock that is pulled with a net force of 80N?
The acceleration of the rock can be calculated using Newton's second law, which states that acceleration is equal to the net force divided by the mass of the object. In this case, the acceleration of the 10 kg rock pulled with a net force of 80N would be 8 m/s^2.
A cart of mass 10kg pulled along a smooth platform by a force of 60N. What is the acceleration of the cart?
F=mass * acceleration 60kg m/s^2=10kg * acceleration 6m/s^2 = acceleration
How does Santa Claus travel from and to the U.S.?
Santa travels on his sleigh, pulled by reindeer.
A 1000 kg automobile is pulled by a horizontal tow line with a force of 800 N What is the automobile's acceleration?
F = m aa = F/m = (800) / (1,000) = 0.8 m/sec2
What is Santa's vehicle called?
Santa travels in a sleigh pulled by reindeer.
