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The limiting friction is given by the expression Mu R. Here mu is the coefficient of friction and 0.2 is the value given as the data.

R is the reaction which equal to mg where m is the mass and here it is 10 kg and g is 9.8 m/s^2

Hence the limiting friction = 0.2 x 10 x 9.8 = 19.6 N.

A force of 19.6 N is enough to make the body to slip

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Q: A body of mass 10 kg is lying on a horizental surface if the cofficient of friction between the body and the surface is 0.2 then answe the following questions1what is the minimum force required to Sli?
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