A bullet hits a wall with a velocity of 20ms and penetrates it upto a distance of 5cmfind the deceleration of the bullet in the wall?

Answer 1

To find the deceleration of the bullet, you can use the equation of motion (v^2 = u^2 + 2as), where (v) is the final velocity (0 m/s as bullet stops), (u) is the initial velocity (20 m/s), (a) is the acceleration (deceleration), and (s) is the distance (5 cm = 0.05 m). Rearranging the equation to solve for acceleration gives you (a = \frac{{v^2 - u^2}}{2s}). Plugging in the values, you can calculate the deceleration of the bullet.