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A car traveling at a velocity of 24 m s is accelerated uniformly at a rate of 2 m s for 8 seconds what is the final velocity of the car?
The final velocity can be calculated using the formula: final velocity = initial velocity + acceleration × time. Given: initial velocity = 24 m/s, acceleration = 2 m/s², and time = 8 seconds. Plugging in the values: final velocity = 24 m/s + 2 m/s² × 8 s = 24 m/s + 16 m/s = 40 m/s. Therefore, the final velocity of the car is 40 m/s.
A car traveling at a velocity of 24 ms is accelerated uniformly at a rate of 2 ms for 8 seconds what is the final velocity?
Given: V0 = 24 m/s, a = 2 m/s2, t = 8 s. (a = acceleration, t = time) Vf = V0 + a t Vf = (24) + (2) (8) = 24 + 16 = 40 m/s.
What is the objects average velocity over a 15 second interval if the object initially at rest experiences an acceleration of 1.7 for 6 sec and travels at that constant velocity for another 9 seconds?
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
What is the velocity of a car that is traveling -50 meters in 5 seconds then 10 meters in 5 seconds?
The average velocity for the entire trip can be calculated as the total displacement over the total time. First find the total displacement (final position - initial position): -40 meters. Then, calculate the total time: 10 seconds. Finally, divide displacement by time to find the average velocity: -4 m/s.
A race car starts from rest and accelerates uniformly of 40ms in 8 seconds. How far will the car travel during the 8 seconds?
The formula for distance traveled with uniformly accelerated motion is d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time. Plugging in the values: d = 0.5 * 40 * 8^2 = 0.5 * 40 * 64 = 1280 meters. Therefore, the car will travel 1280 meters in 8 seconds.
A car traveling at a velocity of 24 m s is accelerated uniformly at a rate of 2 m s for 8 seconds what is the final velocity of the car?
The final velocity can be calculated using the formula: final velocity = initial velocity + acceleration × time. Given: initial velocity = 24 m/s, acceleration = 2 m/s², and time = 8 seconds. Plugging in the values: final velocity = 24 m/s + 2 m/s² × 8 s = 24 m/s + 16 m/s = 40 m/s. Therefore, the final velocity of the car is 40 m/s.
What is the velocity of water traveling 160 feet through a pipe in 25 seconds?
To find the velocity of water traveling through a pipe, you can use the formula: velocity = distance/time. Here, the distance is 160 feet and the time is 25 seconds. Thus, the velocity is 160 feet / 25 seconds = 6.4 feet per second.
A car traveling at a velocity of 24 ms is accelerated uniformly at a rate of 2 ms for 8 seconds what is the final velocity?
Given: V0 = 24 m/s, a = 2 m/s2, t = 8 s. (a = acceleration, t = time) Vf = V0 + a t Vf = (24) + (2) (8) = 24 + 16 = 40 m/s.
A car whose mass is 2000 kg is accelerated uniformly from rest to speed at 15ms in 10 seconds The net force accelerating the car is?
3000 N
A plane is uniformly accelerated from 60 ms to 80 ms in 12 seconds what is the distance traveled by the plane during this period?
((60m/s+80m/s)/2)x12s=840m
What is the deceleration of a car traveling with a velocity of 30 meters per second slowing down to a velocity of 10 meters per second within 10 seconds?
you doing homework???
What is the objects average velocity over a 15 second interval if the object initially at rest experiences an acceleration of 1.7 for 6 sec and travels at that constant velocity for another 9 seconds?
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
What answer of A car accelerates uniformly from rest after five seconds its final velocity is twenty meter per second its acceleration during third second will be?
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
A driver of a car traveling at 52 km per hour applies brakes and accelerates uniformly in opposite directionthe car stops in 5 seconds. how far will it travel before stopping?
0.07km
If rabbit is traveling at 4feet per second and is trying to get to a finish line 4620 feet away how long does it take him?
Velocity (Speed) = Distance ÷ Time, therefore Time = Distance ÷ Velocity. Time = 4620 ÷ 4 = 1155 seconds = 19 minutes 15 seconds
What is the angular velocity of the wheel before braking began if the wheel rotates through 6 radians in 2 seconds as it is uniformly brought to rest?
It was 6 radians per second. Angular acceleration = -3 radians per second2 Initial angular velocity = 6 radians per second. Final angular velocity = zero. Average angular velocity = 3 radians per second. Angular displacement in 2 seconds = 3 x 2 = 6 radians.
What velocity does the student have after five seconds?
Velocity increases after 5 seconds
