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What energy would a diver at the top of a cliff use?
The diver at the top of the cliff would have potential energy due to their position above the ground. This potential energy can be converted into kinetic energy as the diver falls towards the water.
What is the skydivers velocity after two seconds?
We'll assume you mean 2 seconds AFTER he's jumped from the plane. A good estimate would be 9.8m/s times 2 (9.8m/s/s times 2 seconds -- the standard value of the acceleration due to gravity). In two seconds, the velocity would be low enough that air resistance could probably be ignored for purposes of answering your homework. So try 19.6 m/s, unless your teacher gave your data on the air resistance of the sky diver.
A person jumps off a diving board 4.0m above the water's surface into a pool the person's downward motion stops 2.0m below the surface of the water estimate the avg. decleration of the person under wa?
so what you need to do is find the velocity that the person enters the water and then use the equation v sub final squared = v sub initial squared + 2*acceleration(final distance-initial distance). final velocity is zero, find the initial velocity yourself and use 2 as the final distance where the initial distance is 0, solve for acceleration. Easy way: the decelleration would have been twice that provided by gravity because the diver decellerated to zero in half the distance of the dive. The diver starts at zero and hits max velocity in 4 meters then goes from max velocity to zero in 2 meters. 2 x 9.81 m/s2 = ___
A diver springs upward with an initial speed of 1.8meters per second from a 3.0 meter board what is the velocity when the diver reaches the water What is the highest point he reaches above the water?
Vf^2 = Vi^2 +2ad = 1.8m ^2 + 2(-9.8m/s^2)(3.0m) =62.04m/s Vf= sqrt(62.04m/s) =-7.9m/s
A high diver of mass 70 kg jumps off a board 10 m above the water If her downward motion is stopped 2.00 s after she enters the water what average upward force did the water exert on her?
The average upward force exerted by the water can be calculated using the impulse-momentum theorem. First, find the diver's initial velocity before hitting the water using kinematic equations. Then, use the formula F_avg = mΔv/Δt, where m is the diver's mass, Δv is the change in velocity, and Δt is the time over which the force is applied.
A cliff diver plans to jump off a cliff into a river and needs to know the velocity with which she will strike the water. it takes a rock 2.5 seconds to reach the water. what'ld her final velocity be?
Assuming the acceleration due to gravity is -9.81 m/s^2, we can use the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity (0 m/s in this case), a is the acceleration due to gravity, and t is the time taken (2.5 seconds). Plug in the values to get v = 0 + (-9.81 × 2.5) = -24.525 m/s. The negative sign indicates the direction of the velocity, in this case, downwards.
What are the answers to 14.10 punchline Algebra book b marcy math works?
A diver springs from the edge of the ocean with an initial upward velocity of 8 ft/s. How long will it take the diver to reach the water?
How tall is cliff diver at splish splash water park?
473.69 ft. exactly i measured it with my ruler
What energy would a diver at the top of a cliff use?
The diver at the top of the cliff would have potential energy due to their position above the ground. This potential energy can be converted into kinetic energy as the diver falls towards the water.
What is the skydivers velocity after two seconds?
We'll assume you mean 2 seconds AFTER he's jumped from the plane. A good estimate would be 9.8m/s times 2 (9.8m/s/s times 2 seconds -- the standard value of the acceleration due to gravity). In two seconds, the velocity would be low enough that air resistance could probably be ignored for purposes of answering your homework. So try 19.6 m/s, unless your teacher gave your data on the air resistance of the sky diver.
Suppose a diver leaps from the edge of a cliff 80 feet above the ocean with an initial upward velocity of 8 feet per second How long will it take the diver to enter the water below?
Assuming that acceleration dut to gravity is 32 ft/sec2 and that air resistance is insignificant, the answer is 2.5 seconds. To show work, at 8 ft/sec v = at = 32 t t = 1/4 second jumping up and v = 0 before free fall s = 1/2 at^2 = 16t^2 = 16x.25 x .25 = 1 foot so diver free falls 81 feet 81 = 1/2 at^2 so t = 2.25 sec 2.25 + .25 = 2.5 sec
A person jumps off a diving board 4.0m above the water's surface into a pool the person's downward motion stops 2.0m below the surface of the water estimate the avg. decleration of the person under wa?
so what you need to do is find the velocity that the person enters the water and then use the equation v sub final squared = v sub initial squared + 2*acceleration(final distance-initial distance). final velocity is zero, find the initial velocity yourself and use 2 as the final distance where the initial distance is 0, solve for acceleration. Easy way: the decelleration would have been twice that provided by gravity because the diver decellerated to zero in half the distance of the dive. The diver starts at zero and hits max velocity in 4 meters then goes from max velocity to zero in 2 meters. 2 x 9.81 m/s2 = ___
What is the speed of a diver hitting the water from a height of ten meters?
Terminal velocity
The drag force on a falling sky diver is also known as?
Terminal Velocity.
A diver springs upward with an initial speed of 1.8meters per second from a 3.0 meter board what is the velocity when the diver reaches the water What is the highest point he reaches above the water?
Vf^2 = Vi^2 +2ad = 1.8m ^2 + 2(-9.8m/s^2)(3.0m) =62.04m/s Vf= sqrt(62.04m/s) =-7.9m/s
The drag force acting on a falling sky diver is also known as?
Terminal Velocity.
A high diver of mass 70 kg jumps off a board 10 m above the water If her downward motion is stopped 2.00 s after she enters the water what average upward force did the water exert on her?
The average upward force exerted by the water can be calculated using the impulse-momentum theorem. First, find the diver's initial velocity before hitting the water using kinematic equations. Then, use the formula F_avg = mΔv/Δt, where m is the diver's mass, Δv is the change in velocity, and Δt is the time over which the force is applied.
