A force of 5 Kg compresses the springs in series 10cm What will be the total distance that the springs in parallel are compressed?

Answer 1

(Fs) = -(Ks)(Xs) (Fp) = -(Kp)(Xp)

(Fs) = (Fp)

-(Ks)(Xs) = -(Kp)(Xp)

(Ks)(Xs) = (Kp)(Xp)

(Ks) = (1/K1 + 1/K2)^-1 (Kp) = (K1 + K2)

(1/K1 + 1/K2)^-1 (Xs) = (K1 + K2)(Xp)

K1 = K2 = K

(1/K + 1/K)^-1 (Xs) = (K + K)(Xp)

(2/K)^-1 (Xs) = (2K)(Xp)

(K/2)(Xs) = (2K)(Xp)

(1/4)(Xs) = (Xp)

(Xp) = (1/4)(Xs); Let (Xs) = (10)(cm)

(Xp) = (1/4)(10)(cm)

(Xp) = (2.5)(cm)

Answer 2

2.5cm