From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.
If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):
Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules
8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.
If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.
The work done on the crate would be 4000 joules (W = F x d), as work is the product of force (200 N) and distance (20 m).
If the combined center of gravity for a forklift moves outside of the stability triangle, the forklift is at risk of tipping over. This can lead to accidents, injuries, and damage to the forklift and its surroundings. It's crucial to operate the forklift within its stability limits to maintain safety.
If the combined center of gravity moves outside the stability triangle, the forklift becomes unstable and can tip over. This could result in serious accidents and injuries. It is essential to always operate the forklift within the stability triangle to ensure safe and efficient operation.
If the combined center of gravity for a forklift moves outside of the stability triangle, the forklift becomes unstable and is at risk of tipping over. This can lead to accidents, injuries, and damage to the forklift or its surroundings. It's important to always operate forklifts within their stability limits to ensure safety.
The one which says it will fall over.
A rocket that travels 9000 meters in 12.12 seconds moves at 742.5742 meters/second which is approx 1660 mph
20 meters per second
The snail moves 0.3m per minute.
If the combined center of gravity for a forklift moves outside of the stability triangle, the forklift is at risk of tipping over. This can lead to accidents, injuries, and damage to the forklift and its surroundings. It's crucial to operate the forklift within its stability limits to maintain safety.
The work done on the crate would be 4000 joules (W = F x d), as work is the product of force (200 N) and distance (20 m).
A tow motor does just that, tow. A forklift lifts and moves freight.
The unit rate is how far something moves in ONE second. So in this case you divide by 28 (the number of seconds). 12/28=0.4285714285714286 meters a second.
The woman pulls on the crate, but the crate does not move. The woman pulls on the crate and it moves 5m to the right. The woman pulls on the crate and it moves 10m to the right. The woman pulls on the crate and it moves 15m to the right. So, ranking from least to greatest work done by her force would be 1, 2, 3, 4.
If the combined center of gravity moves outside the stability triangle, the forklift becomes unstable and can tip over. This could result in serious accidents and injuries. It is essential to always operate the forklift within the stability triangle to ensure safe and efficient operation.
If the combined center of gravity for a forklift moves outside of the stability triangle, the forklift becomes unstable and is at risk of tipping over. This can lead to accidents, injuries, and damage to the forklift or its surroundings. It's important to always operate forklifts within their stability limits to ensure safety.
To find the speed, you can divide the distance by the time. If an object travels 60 meters in 3 seconds, its speed is 60 meters divided by 3 seconds, which equals 20 meters per second (m/s). This means the object moves at a constant speed of 20 m/s over that time interval.
Just divide the distance by the time. (In this case, the speed in the answer will be in meters per second.)