To find the time the ball was in the air, you can use the time of flight formula: T = 2 * (V * sin(angle)) / g, where V is the initial speed (31 m/s), the angle is 35 degrees, and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, the time of flight comes out to be approximately 3.2 seconds.
The horizontal velocity component of the ball can be calculated using the formula: horizontal velocity = initial velocity * cos(angle). Substituting the values, we get: horizontal velocity = 31 m/s * cos(35 degrees) ≈ 25.3 m/s.
The maximum height attained by the ball can be calculated using the kinematic equation for projectile motion. The formula to calculate the maximum height is (v^2 * sin^2(angle))/(2g), where v is the initial velocity, angle is the launch angle, and g is the acceleration due to gravity. Substituting the values, the maximum height is approximately 15 meters.
The vertical velocity component of the ball can be found by multiplying the initial speed (31 m/s) by the sine of the launch angle (35 degrees). Vertical velocity = 31 m/s * sin(35) ≈ 17.7 m/s. The vertical velocity component is approximately 17.7 m/s.
The key is to recognize that "the angle of INCIDENCE is equal to the angle of REFLECTION", for an 'Elastic' collision. So the answer is 20 degrees.
If the angle of incidence is 45 degrees, then the angle of reflection will also be 45 degrees. This is because the angle of incidence is always equal to the angle of reflection according to the law of reflection.
To round an angle to the nearest 5 degrees, first determine the remainder when the angle is divided by 5. If the remainder is 2.5 degrees or less, round down to the nearest multiple of 5; if it is more than 2.5 degrees, round up to the next multiple of 5. For example, 37 degrees would round to 35 degrees, while 42 degrees would round to 45 degrees.
92 or 91.5 meters would be the maximum height.
900/7 = 128.6 degrees rounded to the nearest tenth
Each exterior is 360/7 = 51.4 degrees to the nearest tenth
The 7 interior angles of an heptagon add up to 900 degrees.
tan-1(0.8) = 38.65980825 degrees or 38.7 degrees to the nearest tenth.
It is 12.2 degrees.
The horizontal velocity component of the ball can be calculated using the formula: horizontal velocity = initial velocity * cos(angle). Substituting the values, we get: horizontal velocity = 31 m/s * cos(35 degrees) ≈ 25.3 m/s.
If you mean an angle of 30 degrees then the hypotenuse is 12.5/sin(30) = 25.0 meters
360 degrees. Is this from Current Science? That's what I'm doing.
60 degrees
70