25.3
The maximum height attained by the ball can be calculated using the kinematic equation for projectile motion. The formula to calculate the maximum height is (v^2 * sin^2(angle))/(2g), where v is the initial velocity, angle is the launch angle, and g is the acceleration due to gravity. Substituting the values, the maximum height is approximately 15 meters.
The maximum height of the ball can be calculated using the formula h = (v^2 * (sin(theta))^2) / (2 * g), where v is the initial velocity (26 m/s), theta is the launch angle (30 degrees converted to radians), and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find that the maximum height attained by the ball is approximately 10.7 meters.
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
The maximum height of a projectile depends on its initial velocity and launch angle. In ideal conditions, the maximum height occurs when the launch angle is 45 degrees, reaching a height equal to half the maximum range of the projectile.
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
25.3
The maximum height attained by the ball can be calculated using the kinematic equation for projectile motion. The formula to calculate the maximum height is (v^2 * sin^2(angle))/(2g), where v is the initial velocity, angle is the launch angle, and g is the acceleration due to gravity. Substituting the values, the maximum height is approximately 15 meters.
The maximum height of the ball can be calculated using the formula h = (v^2 * (sin(theta))^2) / (2 * g), where v is the initial velocity (26 m/s), theta is the launch angle (30 degrees converted to radians), and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find that the maximum height attained by the ball is approximately 10.7 meters.
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
92 or 91.5 meters would be the maximum height.
The maximum height of a projectile depends on its initial velocity and launch angle. In ideal conditions, the maximum height occurs when the launch angle is 45 degrees, reaching a height equal to half the maximum range of the projectile.
45 degrees.
16.1 or 16^^^ GIVE US AN ANSWER, NOT A OPTION. DOUBLE YOU- TEE- EFF
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
The angle of projection significantly influences the maximum height an object can reach. When an object is projected at a higher angle, closer to 90 degrees, a greater portion of its initial velocity is directed upwards, resulting in a higher maximum height. Conversely, lower angles, while providing more horizontal distance, reduce the vertical component of the velocity and thus limit the height achieved. The optimal angle for maximum height is 90 degrees, where all the energy is used for vertical ascent.
There is no maximum height
15.42 degrees