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Since the equation for time=sqrt(2h/g)

set 2 seconds for time and 9.8 for gravity

so 2=sqrt(2h/9.8)

clear the sqrt by squaring both sides

4= 2h/9.8

9.8*4 =2h

(9.8*4)/2 = height.

now that you have the height, you can do v=distance/time

v=height from the equation prior/2 seconds

i hope that works..

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16y ago
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14y ago

Formula: V(final) = V(initial) + at -a=acceleration=9.8m/ss, t=time Assuming the initial velocity is 0 (the rock was just dropped and not thrown)... 2 seconds - velocity = 19.6 m/s 5 seconds - velocity = 49 m/s 10 seconds - velocity = 98 m/s

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14y ago

Acceleration of gravity is 9.8 meters (32.2 feet) per second2.

After 2.5 seconds, the object has reached a speed of (2.5 x 9.8) = 24.5 m/s . . . . . (2.5 x 32.2) = 80.5 ft/sec

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15y ago

68.6 m/s.

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Q: A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?
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