0
A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?
Since the equation for time=sqrt(2h/g)
set 2 seconds for time and 9.8 for gravity
so 2=sqrt(2h/9.8)
clear the sqrt by squaring both sides
4= 2h/9.8
9.8*4 =2h
(9.8*4)/2 = height.
now that you have the height, you can do v=distance/time
v=height from the equation prior/2 seconds
i hope that works..
What else can I help you with?
A rock dropped on the moon will increase its speed from 0 m s to 4.9 m s in about 3 seconds what is the acceleration of the rock?
The acceleration of the rock is calculated by dividing the change in velocity by the time taken. In this case, the change in velocity is 4.9 m/s and the time taken is 3 seconds. Thus, the acceleration of the rock is 4.9 m/s^2.
A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
A rock falls from a cliff 144 ft high How long does it take the rock to reach the ground?
Assuming the rock is dropped (initial velocity is 0), the time it takes for the rock to reach the ground can be calculated using the formula: time = sqrt(2 * distance / gravity). The acceleration due to gravity is approximately 32 ft/s^2. Plugging in the values, the time it takes for the rock to reach the ground would be approximately 3 seconds.
When rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds what is the acceleration of the rock?
The acceleration of the rock would be (1.63 , \text{m/s}^2) (calculated by dividing the change in velocity by the time taken).
Suppose a rock is dropped off a cliff with an initial speed of 0ms. what is the rocks speed after 5 second in ms if it encounters no air resistance?
The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.
A rock is dropped from a cliff and hits the ground 6.0 seconds later How high is the cliff?
176.4 meters
Suppose a rock is dropped off a cliff with an initial speed of 0 What is the rock's speed after 5 seconds in if it encounters no air resistance?
49
If a Rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?
29.4
Suppose a rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 5 seconds in ms if it encounters no air resistance?
49
A rock dropped on the moon will increase its speed from 0 m s to 4.9 m s in about 3 seconds what is the acceleration of the rock?
The acceleration of the rock is calculated by dividing the change in velocity by the time taken. In this case, the change in velocity is 4.9 m/s and the time taken is 3 seconds. Thus, the acceleration of the rock is 4.9 m/s^2.
How high is the cliff if a rock is dropped and you hear the sound after 7 seconds?
S=ut+0.5*a*t2 s=displacement u=intial velocity=0m/s t=time=7seconds a=9.81m/s2 s=0*7+0.5*9.81*72 s=240.345m
A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
Suppose a rock is dropped off a cliff with an initial speed of 0 miles per second What is the rock's speed after 5 seconds in miles per second if it encounters no air resistance?
,033
A rock falls from a cliff 144 ft high How long does it take the rock to reach the ground?
Assuming the rock is dropped (initial velocity is 0), the time it takes for the rock to reach the ground can be calculated using the formula: time = sqrt(2 * distance / gravity). The acceleration due to gravity is approximately 32 ft/s^2. Plugging in the values, the time it takes for the rock to reach the ground would be approximately 3 seconds.
When rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds what is the acceleration of the rock?
The acceleration of the rock would be (1.63 , \text{m/s}^2) (calculated by dividing the change in velocity by the time taken).
A rock is thrown from a cliff and hits the ground 5 seconds later at a distance of 50 meters from the cliff How high was the cliff?
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
