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Since the equation for time=sqrt(2h/g)

set 2 seconds for time and 9.8 for gravity

so 2=sqrt(2h/9.8)

clear the sqrt by squaring both sides

4= 2h/9.8

9.8*4 =2h

(9.8*4)/2 = height.

now that you have the height, you can do v=distance/time

v=height from the equation prior/2 seconds

i hope that works..

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The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.


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Assuming the rock is dropped (initial velocity is 0), the time it takes for the rock to reach the ground can be calculated using the formula: time = sqrt(2 * distance / gravity). The acceleration due to gravity is approximately 32 ft/s^2. Plugging in the values, the time it takes for the rock to reach the ground would be approximately 3 seconds.


When rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds what is the acceleration of the rock?

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Suppose a rock is dropped off a cliff with an initial speed of 0ms. what is the rocks speed after 5 second in ms if it encounters no air resistance?

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