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You don't mention the units in the question, so we're at liberty to choose units

that lead to the simplest calculation. We'll assume that the units are compatible

with the basic formula:

Distance = 1/2 (acceleration) x (time)2

Then distance = (1/2) (34.3) (9)2 = 1,389.15

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12y ago
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14y ago

Note: No units given in the question. No units used in the solution.

The average speed is (73/3.3).

Initial speed = 0.
Final speed = 2 x (73/3.3) = 146/3.3

Acceleration = (change in speed) / (time) = (146/3.3) / (3.3) = 146/10.89 = 13.407 (rounded).

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Q: A rocket initially at rest on the ground accelerates straight upward from rest with constant acceleration 34.3 The acceleration period lasts for time 9 what is the max height?
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