The speed of the stone can be calculated using the equation: speed = distance/time. Given that the stone takes 4 seconds to reach the ground and neglecting air resistance, the speed can be approximated using the formula s = 0.5 * g * t^2, where g is the acceleration due to gravity (approximately 9.8 m/s^2). Substituting the values, the speed of the stone would be approximately 39.2 m/s.
The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.
The rock will have a greater speed when it reaches the ground level compared to the ball thrown horizontally because the rock will be accelerated by gravity as it falls vertically, while the ball thrown horizontally will only have its initial horizontal velocity.
The speed of the ball when it reaches the ground can be calculated using the formula: speed = acceleration due to gravity x time taken. Given that the acceleration due to gravity is approximately 9.81 m/s^2, multiplying it by the time taken (4.5 seconds) gives a speed of approximately 44.145 m/s.
The thrown ball will have a greater speed when it reaches ground level because it has a horizontal component of velocity in addition to the vertical component. The rock only has a vertical component of velocity due to gravity.
Gravity is a force that pulls objects towards the Earth. When an object is dropped, gravity acts on it, causing it to accelerate towards the ground. The speed of the object as it falls increases due to this acceleration until it reaches the ground.
240 ft
29.4/3=9.8m/s2
The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.
The rock will have a greater speed when it reaches the ground level compared to the ball thrown horizontally because the rock will be accelerated by gravity as it falls vertically, while the ball thrown horizontally will only have its initial horizontal velocity.
The speed of the ball when it reaches the ground can be calculated using the formula: speed = acceleration due to gravity x time taken. Given that the acceleration due to gravity is approximately 9.81 m/s^2, multiplying it by the time taken (4.5 seconds) gives a speed of approximately 44.145 m/s.
49
The thrown ball will have a greater speed when it reaches ground level because it has a horizontal component of velocity in addition to the vertical component. The rock only has a vertical component of velocity due to gravity.
Gravity is a force that pulls objects towards the Earth. When an object is dropped, gravity acts on it, causing it to accelerate towards the ground. The speed of the object as it falls increases due to this acceleration until it reaches the ground.
29.4
49
Answer: 44 meters
Answer: 3 seconds