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The altitude of the first stone above the ground is [ H = 100 - 1/2 G T2 ].
The altitude of the second stone is [ H = 25T - 1/2 G T2 ].
The stones meet when their altitudes are the same.
100 + 1/2 G T2 = 25T - 1/2 G T2
Add 1/2 G T2 to each side of the equation:
25 T + GT^2 -100 = 0
They meet when T = 2.15 seconds after the drop-and-toss
Plug that into the expression for the position of the dropped stone:
100 - 1/2 G T2 = 100 - (4.9) (16) = 100 - 78.4 = 21.6 meters from the ground.
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