8 Metres.
40 Metres total, divided by the number of crests (5), equals 8 metres.
When light passes through different mediums, such as air, water, or glass, the distance between waves (wavelength) can change. This is because the speed of light varies in different mediums, causing the wavelength to either increase or decrease.
The wavelength of the wave can change as it passes into Medium 2, depending on the refractive indices of the mediums. If the wave enters a medium with a higher refractive index, the wavelength will decrease. If it enters a medium with a lower refractive index, the wavelength will increase.
Just use the relationship: speed (of the wave) = frequency x wavelength. If the frequency is in hertz (cycles/second), and the wavelength in meters, then of course the speed will be in meters/second.
Speed = (wavelength) x (frequency) = (12) x (1/3) = 4 meters per second
Frequency refers to how many waves pass a fixed point in a unit of time. Frequency is measured in Hertz, or Hz, and one Hertz means a single wave passes a given fixed point in one second. Wavelength refers to the length of an entire wave, so either from crest to crest or trough to trough. If you know how many waves pass a given point in a unit of time, which is frequency, and how long the waves are, which is wavelength, you can find the wave's speed. For example, if a wave has a frequency of 10 Hz, so ten waves pass a given point in a second, and it has a wavelength of four meters, you multiply the frequency by the wavelength to find that the waves are traveling at 40 meters per second.
When light passes through different mediums, such as air, water, or glass, the distance between waves (wavelength) can change. This is because the speed of light varies in different mediums, causing the wavelength to either increase or decrease.
The wavelength of the wave can change as it passes into Medium 2, depending on the refractive indices of the mediums. If the wave enters a medium with a higher refractive index, the wavelength will decrease. If it enters a medium with a lower refractive index, the wavelength will increase.
The particles of the medium move up and down as the wave passes. The crests and troughs of the waves move with the wave.
Just use the relationship: speed (of the wave) = frequency x wavelength. If the frequency is in hertz (cycles/second), and the wavelength in meters, then of course the speed will be in meters/second.
The speed of the light decreases, and its wavelength increases by the same factor.
Speed = (wavelength) x (frequency) = (12) x (1/3) = 4 meters per second
Frequency refers to how many waves pass a fixed point in a unit of time. Frequency is measured in Hertz, or Hz, and one Hertz means a single wave passes a given fixed point in one second. Wavelength refers to the length of an entire wave, so either from crest to crest or trough to trough. If you know how many waves pass a given point in a unit of time, which is frequency, and how long the waves are, which is wavelength, you can find the wave's speed. For example, if a wave has a frequency of 10 Hz, so ten waves pass a given point in a second, and it has a wavelength of four meters, you multiply the frequency by the wavelength to find that the waves are traveling at 40 meters per second.
The wavelength of the light wave must increase as it passes from glass into air. This is because light travels faster in air than in glass, causing the wavelength to stretch out as the wave exits the denser medium.
The speed of the wave increases, the frequency remains constant and the wavelength increases. The angle of the wave also changes.
The frequency of light remains constant when passing from air to water. However, the speed of light changes due to the change in the medium, causing the wavelength to change. This change in wavelength results in the light bending or refracting at the interface between air and water.
When light passes through a narrow slit, the phenomenon of wavelength diffraction causes the light waves to spread out and interfere with each other. This results in a pattern of alternating bright and dark fringes on a screen placed behind the slit. The width of the slit and the wavelength of the light determine the spacing of these fringes.
The wavelength of a violet ray in vacuum is 400nm. The refractive index of diamond is about 2.42. Using the formula λ'=λ/n where λ' is the wavelength of the ray in a material, λ is the wavelength in vacuum and n is the refractive index of the material, we get λ'=165nm.