At the center of earth or any other heavenly body.
Yes, when an object is resting on a table, the acceleration due to gravity acts vertically downward, but the table exerts an equal and opposite force (normal force) on the object in the upward direction, canceling out the effect of gravity. Therefore, the net acceleration on the body is zero.
In the case of a parachute, the person and parachute fall at a constant speed once the forces acting on them are balanced. This means that the net acceleration, including gravity, is zero. Gravity is still acting on the person and parachute, but it is balanced by the drag force exerted by the parachute, resulting in a constant speed descent.
For example, an object thrown upwards, when it is at its highest point. This situation is only possible for an instant - if the acceleration is non-zero, the velocity changes, and can therefore not remain at zero.
acceleration due to gravity of earth is 9.8ms-2
I suppose you are asking about what forces change when acceleration due to gravity changes. In this case, the formula for forces concerning acceleration due to gravity is as such: fg=mg. When acceleration due to gravity(g) changes, it affects the force of gravity which is also known as the weight of the object. This is shown as fg.
Acceleration due to the earth's gravity is zero at the center of the Earth because at that point the mass of the earth is equally distributed in all directions, so pulling equally in all directions for a net zero pull. Simplistically, acceleration due to gravity decreases as distance from the center decreases. At the center the distance is zero, hence gravity is zero.
No. At the centre of the earth the acceleration due to gravity is ZERO
Yes, when an object is resting on a table, the acceleration due to gravity acts vertically downward, but the table exerts an equal and opposite force (normal force) on the object in the upward direction, canceling out the effect of gravity. Therefore, the net acceleration on the body is zero.
In the case of a parachute, the person and parachute fall at a constant speed once the forces acting on them are balanced. This means that the net acceleration, including gravity, is zero. Gravity is still acting on the person and parachute, but it is balanced by the drag force exerted by the parachute, resulting in a constant speed descent.
Yes, satellite orbiting the Earth in a Geo-Stationary Orbit has 0 Velocity relative to a point on the Earth, BUT it experience the 'Pull' (acceleration) of Gravity, which prevents it from escaping its Orbit. The Gravity is LESS than that at the surface of the Earth, but not 0. The feeling of WEIGHTLESSNESS is not due to Zero Gravity, but due to the fact that Object is FALLING through its Orbit. A Person Falling "feels" Zero Gravity.
Answer:Yes, but only instantaneously.Consider a thrown ball moving directly upward. At the highest point of its trajectory, the instanataneous velocity (the velocity at that precise instant) is zero even while the acceleration due to gravity remains non zero.
For example, an object thrown upwards, when it is at its highest point. This situation is only possible for an instant - if the acceleration is non-zero, the velocity changes, and can therefore not remain at zero.
acceleration due to gravity of earth is 9.8ms-2
Acceleration due to gravity on Saturn = 11.171 m/s2 (9.807 m/s2 on Earth)
I suppose you are asking about what forces change when acceleration due to gravity changes. In this case, the formula for forces concerning acceleration due to gravity is as such: fg=mg. When acceleration due to gravity(g) changes, it affects the force of gravity which is also known as the weight of the object. This is shown as fg.
Yes, the acceleration of the ball will change. Initially, the acceleration is downward (due to gravity) while the ball is speeding up. As it reaches its peak height, the acceleration becomes zero. On the way back down, the acceleration is again downward and the ball speeds up due to gravity.
The vertical component of the acceleration vector is the acceleration due to gravity (9.81 m/s^2 downward). The horizontal component of the acceleration vector is zero since there is no acceleration acting in the horizontal direction (assuming no external forces).