To solve this problem, you must first calculate the force in the horizontal direction which would be 125*cos(59) Newtons (draw a triangle if this helps and then use trig). Next, you must solve for the mass of the sled which is 845/9.8. Finally, use the equation F=ma:
108.5 = 86.2*a
a = (approximately) 1.26 meters per second
The vertical velocity component changes due to the effect of gravity, which causes acceleration in the downward direction. The horizontal velocity component remains constant because there are no horizontal forces acting on the projectile (assuming air resistance is negligible).
No, assuming no air resistance, there will be a constant downward acceleration of 9.8 meters per second square (assuming standard gravity). The vertical component of the velocity will be zero at the top of the trajectory.
The acceleration of a falling object near the Earth's surface is approximately 9.81 m/s^2, assuming air resistance is negligible. This acceleration is due to gravity and causes the object to increase its velocity by 9.81 m/s every second it falls.
Yes, it can, if the initial velocity vector of an object was in opposite direction to its constant acceleration. Example: Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
The vertical component of the acceleration vector is the acceleration due to gravity (9.81 m/s^2 downward). The horizontal component of the acceleration vector is zero since there is no acceleration acting in the horizontal direction (assuming no external forces).
The vertical velocity component changes due to the effect of gravity, which causes acceleration in the downward direction. The horizontal velocity component remains constant because there are no horizontal forces acting on the projectile (assuming air resistance is negligible).
Assuming negligible air resistance, the acceleration of a projectile near the Earth's surface is always the gravitational 9.81 m/sec/sec downwards, regardless of where in the trajectory the projectile is.
Acceleration is a change in velocity. Assuming a constant direction, if you're speeding up that is positive acceleration. If you are slowing down, that's negative acceleration. Either way you are accelerating.
Assuming that there is negligible energy loss and that maximum acceleration is achieved, F = ma F = (0.07)(3800) F = 266N
If the speed of the object doesn't change, then yes.
No, assuming no air resistance, there will be a constant downward acceleration of 9.8 meters per second square (assuming standard gravity). The vertical component of the velocity will be zero at the top of the trajectory.
The acceleration of a falling object near the Earth's surface is approximately 9.81 m/s^2, assuming air resistance is negligible. This acceleration is due to gravity and causes the object to increase its velocity by 9.81 m/s every second it falls.
1g, 9.82 m s^-2, gives a 0-60 (mph) time of 2.73 seconds, from rest, assuming negligible air resistance. Not many cars can do that.
Any change of velocity, including a decrease of speed, is described and measured as acceleration. Assuming the velocity and acceleration vectors point in the same direction, then in the case of decreasing speed, the magnitude of the acceleration is a negative value. Negative acceleration is often called deceleration, but that is just a special case of acceleration.
The cart's acceleration will be directly proportional to the net force applied to it. If the force remains constant, the acceleration will also remain constant, assuming no other external factors are affecting the cart's motion.
Yes, it can, if the initial velocity vector of an object was in opposite direction to its constant acceleration. Example: Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
The vertical component of the acceleration vector is the acceleration due to gravity (9.81 m/s^2 downward). The horizontal component of the acceleration vector is zero since there is no acceleration acting in the horizontal direction (assuming no external forces).