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An arrow is shot vertically upward from the ground with velocity of 1.22 ms. How long will it take the arrow to reach a point 4.80 m above the ground?
Just use s = ut - 1/2 g t^2
Here s = 4.8 m, u = 1.22 m/s and of course g = 9.8 m/s^2
Plug and you will get a quadratic equation. Right from this you can get the value of t.
What else can I help you with?
How is possible for air pressure to exert a vertically upward force on a ceiling?
Air pressure exerts a vertically upward force on a ceiling due to the weight of the air above pushing down on the air below. This pressure difference results in a net force that pushes upward on the ceiling, according to Newton's third law of motion.
When a buulet is fired upward verticallyit gains in?
When a bullet is fired upward vertically, it gains potential energy due to the increase in its height above the ground. As the bullet rises, its kinetic energy decreases and is converted into potential energy until it reaches its maximum height.
Sketch velocity-time graph when an object is thrown vertically upward?
The velocity-time graph of an object thrown vertically upward will have a parabolic shape. The velocity will decrease from the initial positive value until reaching zero at the peak of its motion, then become negative as it falls back down. The velocity-time graph will be symmetric about the point where the object reaches its highest point.
What is an example problem of speed and velocity?
An example problem involving speed is calculating the average speed of a car that travels 100 miles in 2 hours. An example problem involving velocity is determining the velocity of a ball thrown upward with an initial velocity of 20 m/s at a height of 40 meters above the ground.
When a bullet is fired upwards vertically it gains?
When a bullet is fired upwards vertically, it gains potential energy as it rises due to the increase in its height above the ground. This potential energy is converted into kinetic energy as the bullet falls back to the ground. The total mechanical energy of the bullet remains constant neglecting air resistance.
If an object is thrown upward with an initial velocity of 32 feet per second from 40 feet above the ground write the height equation?
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
When a ball is thrown vertically upward at initial velocity of 15 meter per second Find the position and velocity after 1.0 second and 40 second after leaving your hand?
1 sec : position = 10.1 metres above your hand, velocity = 5.2 ms^-1.40 sec : position = 7240 metres below your hand, velocity = 377 ms^-1 downwards.
How is possible for air pressure to exert a vertically upward force on a ceiling?
Air pressure exerts a vertically upward force on a ceiling due to the weight of the air above pushing down on the air below. This pressure difference results in a net force that pushes upward on the ceiling, according to Newton's third law of motion.
When a buulet is fired upward verticallyit gains in?
When a bullet is fired upward vertically, it gains potential energy due to the increase in its height above the ground. As the bullet rises, its kinetic energy decreases and is converted into potential energy until it reaches its maximum height.
Sketch velocity-time graph when an object is thrown vertically upward?
The velocity-time graph of an object thrown vertically upward will have a parabolic shape. The velocity will decrease from the initial positive value until reaching zero at the peak of its motion, then become negative as it falls back down. The velocity-time graph will be symmetric about the point where the object reaches its highest point.
Question-1 A body is thrown vertically upwards The distance st above the ground after t seconds is given by st 20t-5t2 meters?
The equation for vertical motion is y = v0t + .5at2. y is vertical displacement v0 is initial vertical velocity a is acceleration (in meters, normal gravitational acceleration is about -9.8 m/s/s, assuming positive y is upward displacement and negative y is downward displacement)
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
A ball is thrown vertically upward. What are its velocity and acceleration when it reaches its maximum altitude What is the acceleration of the ball just before it hits the ground?
At the maximum height the ball will be completely stopped from moving upward or downward; thus the speed of the ball would be 0 mph. The ball is only stopped for a split second and then it begins moving downward, then increasing at 9.81m/s^2 until it reaches maximum velocity.
What is an example problem of speed and velocity?
An example problem involving speed is calculating the average speed of a car that travels 100 miles in 2 hours. An example problem involving velocity is determining the velocity of a ball thrown upward with an initial velocity of 20 m/s at a height of 40 meters above the ground.
A tennis ball is dropped from 1.55 m above the ground It rebounds to a height of 0.824 mWith what velocity does it hit the ground?
31 m/s
An object is thrown vertically upward when does it reach maximum height?
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
What height is reached by a 4.0kg ball that is thrown vertically up into the air with an initial velocity of 8.5ms1 if by the time it is height (h) metres above the starting point it has a velocity of?
Height reached = 3.7 metres.The mass of the ball is not really relevant.
