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An internal explosion breaks an object initially at rest into two pieces one of which has 2.3 times the mass of the other If 15000 J is released in the explosion how much kinetic energy does each?
Wiki User
∙ 15y ago
I don't think you can get a numerical answer without knowing the value of one of the masses. From conservation of momentum P1 = P2 = P (started from rest so momentums must be equal & opposite) From conservation of energy 15000 = K1 + K2 You can write kinetic energy in terms of momentum as; K = P^2/2m, so 15000 = P1^2/2m + P2^2/2M 15000 = P^2/2m + P^2/2M where M =2.3m So you have two unknowns P & m and no more equations. If you knew m you could solve for P and then find each K. I think I found it. From P1 = P2 or Mu =mv then (2.3)u = v Then K1 = (1/2)Mu^2 = (1/2)(2.3)mu^2 and K2 = (1/2)mv^2 = (1/2)m(2.3)(2.3)u^2 So K2 = (2.3)K1 Then 15000 = K1 + K2 = (3.3)K1 and K1 = 4545.5J Then K2 = 15000 - 4545.5 = 10,454.5J
Wiki User
∙ 15y ago
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