If, as you say, its acceleration is "constant", then the average is exactly equal to that constant.
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
Yes, it can, if the initial velocity vector of an object was in opposite direction to its constant acceleration. Example: Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
At terminal velocity (constant velocity), the acceleration is zero, but prior to that, there is a downward acceleration.
No.Acceleration is a measure of the rate of change of velocity (speed & direction). If acceleration is decreasing (but still above zero) then this means that the rate at which the speed is increasing in this direction is decreasing.As long as the downward acceleration is greater than zero then the skydiver's speed is still increasing.Once terminal velocity is reached then downward acceleration will equal zero (speed is constant).If the downward acceleration falls below zero (as will happen once his parachute is deployed for instance) then this means he is slowing down.
Horizontal . . . acceleration is zero, speed is constant Vertical . . . acceleration is 'G' downward, speed constantly increases downward
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
If it is gravitational acceleration then it it is positive in downward and negative in upward direction..if it is not gravitational acceleration then it is depending upon the value of acceleration.
Of course. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
Yes, it can, if the initial velocity vector of an object was in opposite direction to its constant acceleration. Example: Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
At terminal velocity (constant velocity), the acceleration is zero, but prior to that, there is a downward acceleration.
No.Acceleration is a measure of the rate of change of velocity (speed & direction). If acceleration is decreasing (but still above zero) then this means that the rate at which the speed is increasing in this direction is decreasing.As long as the downward acceleration is greater than zero then the skydiver's speed is still increasing.Once terminal velocity is reached then downward acceleration will equal zero (speed is constant).If the downward acceleration falls below zero (as will happen once his parachute is deployed for instance) then this means he is slowing down.
Constant acceleration
Horizontal . . . acceleration is zero, speed is constant Vertical . . . acceleration is 'G' downward, speed constantly increases downward
acceleration of a falling body is 9.8m/s*s and its direction is vertically downward.
Then - according to Newton's Second Law - you would have more acceleration downward.
One answer to this is that all object are in motion all of the time relative to all other objects. With that said, in the context of permanent halt" the only way that an object can be perceived as "halted" is by another object with the same velocity.
Yes. For instance, if you throw an object up, then (ignoring air friction) it will have a constant downward acceleration of about 9.8 meters/second squared. After a while, this acceleration will make it go downwards again.