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An object 5 millimeter high is located 15 millimeters in front pf a plane mirror How far from the mirror is the image located?
The image of the object in a plane mirror is located at the same distance behind the mirror as the object is in front of it. Therefore, the image of the object would be located 15 millimeters behind the mirror.
An object is 51 millimeters from a diverging lens the object has a height of 13 millimeters and then image height is 3.5 millimeters How far in front of the lens is the image located?
The image distance can be calculated using the lens formula: 1/f = 1/d_o + 1/d_i, where f is the focal length of the lens, d_o is the object distance, and d_i is the image distance. Given that the object distance (d_o) = 51 mm and object height = 13 mm, image height = -3.5 (negative since it is inverted), we can use the magnification formula to find the image distance (d_i). The equation for magnification is M = -d_i/d_o = -hi/ho, where hi is the image height and ho is the object height. Solving these equations will give the image distance in front of the lens.
An object 5 millimeter high is located 15 millimeter in front of a plane mirror How far from the mirror is the image located?
The distance between the object and mirror is 15 mm. The distance between the image and mirror is 15 mm. Therefore, the distance between the image and object is 15 mm plus 15 mm which equals 30 mm.
Which type of lens shrinks the image in front of it rather than magnifies it?
A diverging lens, also known as a concave lens, shrinks the image in front of it. This type of lens causes light rays to diverge, which results in the image being smaller than the object.
The front view of an object is drawn on the what?
The front view of an object is drawn on the elevation or front elevation of a drawing. This view shows the object as if it were being viewed directly from the front.
An object is located 51 millimeter from a diverging lens the object has a height of 13 millimeter and the image heightg is 3.5 millimeters how far in front of the lens is the image located?
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An object is located 51 millimeters from a diverging lens the object has a height og 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
hi/ho = di/do di = dohi/ho di = (51mm)(3.5mm)/(13mm) di = 14mm * rounded to 2 significant figures The image would be 14mm in front of the lens.
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
Since the image height is smaller than the object height, it is a virtual image. Using the thin lens equation (1/f = 1/d_o + 1/d_i), where d_o is the object distance and d_i is the image distance, and assuming a diverging lens, the image distance is found to be -17.17 mm. This means the image is located 17.17 mm in front of the lens.
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image is 3.5 meters how far in front of the lens is the image located?
13.7 millimetersThis answer is correct, but the formula is most important.The formula is:Hi = height of imageHo = height of objectSi = Distance of image from lensSo = Distance of object from lensYou are trying to find Si, so that is your unknown.Here is your formula: Hi/Ho = Si/SoOr in this case: 3.5/13 = Si/51The rest is basic algebra.Good luck!You can use the ratio equation; (Image Height)/(object height) = - (image location)/(object location) In your case you will get a negative location which means the image is on the same side of the lens as the incoming light.
An object is 5 millimeters high is located 15 millimeters in front of a plane mirror how far from the mirror is the image located?
The image will be located the same distance behind the mirror as the object is in front of it, so the image will be 15 millimeters behind the mirror.
An object 5 millimeters high is located 15 millimeters in front of a plane mirror How far from the mirror is the image located?
15 millimeters.
An object 5 millimeters high is located 15 millimeters in front of a plane mirror. How far from the mirror is the image located?
30 millimeters
An object 5 millimeter high is located 15 millimeters in front pf a plane mirror How far from the mirror is the image located?
The image of the object in a plane mirror is located at the same distance behind the mirror as the object is in front of it. Therefore, the image of the object would be located 15 millimeters behind the mirror.
If an object 5 millimeters high is located 15 millimeters in front of a plane mirror How far from the mirror is the image located?
The answer is 15 millimeters behind the mirror, and the distance from the actual object to the image is 30 millimeters. Plane mirrors have a flat focus that places the image as far behind the mirror as you are in front of it.
An object is 51 millimeters from a diverging lens the object has a height of 13 millimeters and then image height is 3.5 millimeters How far in front of the lens is the image located?
The image distance can be calculated using the lens formula: 1/f = 1/d_o + 1/d_i, where f is the focal length of the lens, d_o is the object distance, and d_i is the image distance. Given that the object distance (d_o) = 51 mm and object height = 13 mm, image height = -3.5 (negative since it is inverted), we can use the magnification formula to find the image distance (d_i). The equation for magnification is M = -d_i/d_o = -hi/ho, where hi is the image height and ho is the object height. Solving these equations will give the image distance in front of the lens.
When an object is placed 8 millimeters from a concave spherical mirror a clear image can be projected on a screen 16 millimeters in front of the mirror. If the object has a height of 4 millimeters the?
c. 8 millimeters
An object is located 15millimeters from a diverging lens the object has a height of 13 mm and the image height is 3.5 mm how far in front of the lens is the image located?
Using the expression v/u = Image size / object size we can find the value of v. v = 15 * 3.5/13 = 4 (nearly) So approximately at a distance of 4 mm in front of the lens the image is located on the same side of the object.
