the buoyant force acting on it.
If the weight of the water displaced is less than the weight of the object, the object will sink. This is because the buoyant force acting on the object is not enough to counteract its weight. As a result, the object will continue to sink until it reaches a point where the buoyant force equals its weight, leading to equilibrium.
An object will sink in water if its density is greater than the density of water. This means that the weight of the object is greater than the buoyant force acting on it. Consequently, the object displaces less water than its weight.
It will sink when the object is placed in water.
No, an object will float if it is less dense than water. If an object is less dense than water, it will displace an amount of water equal to its weight, causing it to float.
Density can also be considered volume in this question meaning that the object will sink.
An object will sink if it has a greater density than water. In this case, the weight of the water displaced by the object is less than the weight of the object.
If the weight of the water displaced is less than the weight of the object, the object will sink. This is because the buoyant force acting on the object is not enough to counteract its weight. As a result, the object will continue to sink until it reaches a point where the buoyant force equals its weight, leading to equilibrium.
An object will sink in water if its density is greater than the density of water. This means that the weight of the object is greater than the buoyant force acting on it. Consequently, the object displaces less water than its weight.
The weight does not determine if an object will float in water. If an object has a DENSITY that is more than the density of water then it will sink, if it's density is less than the density of water it will float.
It will sink when the object is placed in water.
Archimedes principle states that : The force of buoyancy is equal to the weight of the displaced water. If the weight of the water displaced is less than the weight of the object , the object will sink. Otherwise the object will float , with the weight of the water displace equal to the weight of the object.
No, an object will float if it is less dense than water. If an object is less dense than water, it will displace an amount of water equal to its weight, causing it to float.
Density can also be considered volume in this question meaning that the object will sink.
If the weight of an object is greater than the weight of the water it displaces, the object will sink. This is because the buoyant force exerted by the water on the object is not enough to counteract the object's weight, resulting in it sinking in the water.
When an object is placed in water, it will experience a buoyant force equal to the weight of the water displaced. If the object's density is less than that of water, it will float. If it is greater, it will sink.
Whether an object will float or sink in water will depend on its volume and weight. If the weight of the displaced water is more than that of the body, the body will float. On the other hand if the weight is the displaced water is less than that of the body, the body will sink. Again if both of them are equal, the body will partially sink. Sea water contains salt. So its density is more and consequently, the weight of the sea water is more. So there is more chance of a ship to float in sea water than in river water. ADD: It depends on the density of the object. If an object is denser than water, it will sink. If it is less dense than water, it will float.
An object will sink in water if its weight is greater than the buoyant force acting on it. The weight of an object is determined by its mass and the force of gravity acting on it. If the weight of the object exceeds the buoyant force (equal to the weight of the water displaced by the object), it will sink.