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That's a correct statement. Although you didn't ask a question, I'll go on and add to it:

The frequency and wavelength of any wave phenomenon, not only sound, change

in exact inverse proportion, so that their product is constant. That product is the

speed of the wave.

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The longer the wavelength the lower the frequency. If there is a high frequency it will have a short wavelength

As the frequency increases, the wavelength decreases. This is true for light and other electromagnetic radiation as well as sound.

Q: As the frequency of sound waves increases the wavelength of the sound dereases.?

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Its wavelength increases and its frequency decreases

We got the formula: speed of medium c = frequency f times wavelength lambda. f = c / lambda lambda = c / f If c increases, also f increases. c is proportional to f, if lambda stays constant. If c increases, also lambda increases. c is proportional to lambda, if fstays constant.

Its wavelength increases and its frequency decreases

frequency = 1/time? If frequency increases, times decreases, so the wave length decreases

It just is. Sound behaves like a wave, and the pitch of the sound affects the wavelength. And wavelength is directly related to the frequency. A high pitched sound has a a shorter wavelength and a higher frequency than a low-pitched sound.

Related questions

frequency of wave is inversely proportional to wavelength

Wavelength.

A) wavelength B) frequency C) velocity D) amplitude

Velocity increases when sound waves travel from gas medium to solid medium. As velocity = frequency * wave length and the frequency does not change, v is directly proportional to the wave length... Hence the wavelength increases.

The speed of the wave increases, the frequency remains constant and the wavelength increases. The angle of the wave also changes.

Its wavelength increases and its frequency decreases

We got the formula: speed of medium c = frequency f times wavelength lambda. f = c / lambda lambda = c / f If c increases, also f increases. c is proportional to f, if lambda stays constant. If c increases, also lambda increases. c is proportional to lambda, if fstays constant.

Its wavelength increases and its frequency decreases

frequency = 1/time? If frequency increases, times decreases, so the wave length decreases

It just is. Sound behaves like a wave, and the pitch of the sound affects the wavelength. And wavelength is directly related to the frequency. A high pitched sound has a a shorter wavelength and a higher frequency than a low-pitched sound.

Kind of. The pitch of a sound wave is its frequency, and because frequency = 1 / wavelength its pitch is related to the wave length. So to answer, no, the pitch of sound is not the wavelength itself, rather it is the inverse of the wavelength ( 1/wavelength)falseACJM

If you change sound's frequency and hold the velocity constant, the sound's wavelength also changes. If you change sound's frequency and keep the wavelength constant, then velocity also changes.