When you move a fulcrum as close as you can to the effort force and farthest away from the load, you are pushing on the short end of the lever, so it requires the most effort force to push on the lever and lift up the load.
When you move the fulcrum farther away from the effort force and closer to the load, you are pushing on the long end of the lever, so it requires less effort force to lift the load.
When a force advantage is attained, typically a distance disadvantage follows. With machines, you never get something for nothing. However in this case, mechanical advantage, speed ratio and things like efficiency and work/joules are involved. To me, these calculations and problem solving situations are tedious and I refuse to waste my time on them lol :) Have a great Thursday mate! Haha
Remember that (force x distance) is 'work', work is the same as 'energy', and you
can't get more out than you put in.
So if the output force is greater than the input force, then the output distance must be
less than the input distance, so that the product of the two is no more at the output
than it was at the input.
I think this is the answer: The effect on the effort force when increasing the distance is the bigger the distance the less effort force required.
F=ma
So assuming mass remains constant, as Force increases, acceleration also increases.
idkk
by increasing effort distance hence reducing the effort needed to work
The effort needed would increase.
confusing
The effort required is directly proportional to the sine of the angle of inclination.Since the sine of an angle increases with increase in angle, therefore the effort required also increases.
The length of the "effort arm" of the lever clearly has a great influence on the 'effort' the pusher must input to the lever in order to do the job. But in terms of the "work" done ... in the formal sense of Work as defined in Physics = (force) x (distance) ... the length of the effort arm should have no effect on the quantity of work.
by increasing effort distance hence reducing the effort needed to work
The effort needed would increase.
confusing
Transformers increase and decrease voltage as needed. PLATO
Not usually. They can convert effort into distance and things like that, but the overall energy is about the same.
The effort required is directly proportional to the sine of the angle of inclination.Since the sine of an angle increases with increase in angle, therefore the effort required also increases.
increases the distance needed to stop your car
If you are thinking of Effort as the FORCE required to move an Object, then the formula is: F = M x A, force = Mass x Acceleration If you are thinking of Effort as the amount of WORK done (in Scientific terms), then the formula is: Work = Force x Distance
Do the following factors increase or decrease as one moves to higher magnifications with the microscope? Resolution, working distance, amount of light needed, and depth of field
they were needed
To do this you first have to calculate your ideal mechanical advantage (IMA). The IMA is equal to the effort distance (the distance from the fulcrum to where you will apply the effort) divided by the load distance (the distance from the fulcrum to the load). You can then set your IMA equal to your acutal mechanical advatage (AMA) which assumes 100% efficiency. The AMA is equal to the load force (the weight of what you are lifting) divided by the effort force (the # you are looking for). So, for example, if your IMA is 5 and your load force is 500 lbs: 5=500/effort force. Therefore the effort force would be 100 pounds.
A relationship between two of it are when load come closer to fulcrum, you need more effort to use. But if load go far away from the fulcrum, you need less effort to use. A relationship between two of it are when load come closer to fulcrum, you need more effort to use. But if load go far away from the fulcrum, you need less effort to use.