Just convert all the temperatures to Kelvin (add 273 to the Celsius temperature). The volume is directly proportional to the absolute (Kelvin) temperature.
Volume will increase. Think of it this way. If you heat a gas, it gets hotter. When a gas gets hotter, the atoms/molecules are "more active" and the pressure and/or the volume will go up. If your experiment with heating this gas sample must have a constant pressure, then volume will have to increase to give all those "more active" atoms/molecules more play room to prevent the pressure from going up.
The question cannot be answered because there are no units given for the pressure not temperature.
Thermal noise is the noise generated by thermal agitation of electrons in a conductor. The noise power "P" in Watts , is given by "P=KTB". The movement or agitation of atoms in conductors and resistors is somewhat random and determined by the temperature of the conductor or resistor. The random movement of electrons is brought about bythermal agitation of the atoms that tends have increased energy as the temperature rises. This random movement gives rise to electrical voltages within the circuitry known as either, thermal noise, resistor noise, Johnson noise or circuit noise. This noise is existent across the frequency spectrum, meaning the more bandwidth occupied the likelihood of greater exposure.Example:K = Boltsmans Constant = 1.3807x10^-23T = Temperature (Kelvin) = 273K + 20 º CB = Bandwidth (Hz) = 180x10^3Noise Power = K x T x B
Air is already in evaporated state(gas) . however the rate of evaporation decreases in the sense its volume decreases(less space is occupied by the molecules)
Convert the volume and pressure to STP using the combined gas law: P1 V1 / T1 = P2 V2 / T2 Once you know how many liters you have at STP (273K and 1 atmosphere), you know the mass of the gas because 22.4L of gas is one mole. Just convert moles back to mass by multiplying by the GMW (atomic weight) for that particular gas. If you know mass and volume, the density is simply mass/volume. PV/RT=n will also find you the moles (n). Say you have 1 Liter of Oxygen at 250K at 1atm. What is its density? * P1 = 1.000atm * P2 = 1.000atm * V1 = 1.000L * V2 = X * T1 = 250.0K * T2 = 273.0K Since pressure is constant, it cancels out of the combined gas law and leaves you with Charles' law (V1 / T1 = V2 / T2): * 1.000L • 273.0K/250.0K = 1.092L * 1.092L of a gas at STP is 0.0488 mol (as long as it behaves ideally) * Oxygen's (O2) GMW is 31.988 grams/mol * 0.0488 mol • 31.988 grams/mol = 1.561 grams * That means that at your original temperature, you had 1.561 grams of a gas that occupied 1 Liter. Its density at that temperature would be 1.561 grams/liter You can shortcut all that if you are holding pressure constant with: GMW • (273K / T1) / 22.4 L/mol = density in grams/liter. If your pressure is changing you'll need to figure that in: GMW • (P1 • 273K / P2 • T1) / 22.4 L/mol = density in grams/liter. DON'T FORGET TO CONVERT YOUR TEMPERATURE TO ABSOLUTE (KELVIN)!!!! All that will only work for gases for which you know the composition (and so you are able to obtain the GMW). If you don't know the composition you will have to find it by experimentation. If the gas ceases to behave ideally (e.g., it condenses at that temperature) the above will also not work.
A fixed quantity of gas at a constant pressure exhibits a temperature of 27 degrees Celsius and occupies a volume of 10.0 L. Use Charles's law to calculate: the temperature of the gas in degrees Celsius in atmospheres if the volume is increased to 16.0 L
You can calculate the cost per occupied room by evaluating all of the costs of each occupied room such as the cost of cleaning, maintenance or repairs. The addition of all of these costs together will give you the cost per occupied room in your building.
Volume occupied divided by weight
Malta was never occupied by German or Italian troops, though it was under constant attscks from 1940 to 1943.
Volume will increase. Think of it this way. If you heat a gas, it gets hotter. When a gas gets hotter, the atoms/molecules are "more active" and the pressure and/or the volume will go up. If your experiment with heating this gas sample must have a constant pressure, then volume will have to increase to give all those "more active" atoms/molecules more play room to prevent the pressure from going up.
Room revnue divided by total no. Of room occupied
Number of rooms occupied divided by total rooms in hotel times 100 For example if there are 50 rooms occupied and 200 rooms in the hotel, then 50/200 x 100 = 25% occupied
sqrt(101N)
The ideal gas equation is a good approximation PV = nRT where P = pressure, V is equal to volume, n = moles of substance, using the molar weight, R is the gas constant 8.315 j K-1 Mol-1, T is the temperature in kelvin, P is the pressure in atmospheres, and V is volume. a useful conversion is to change the jolues component in the gas constant to N -m and convert atmospheres to the same.
Average number of nights occupied per room = Number of nights occupied from January to December / Number of rooms.Occupancy rate = 100 * Average number of nights occupied per room /365
54 liters at STP (standard temperature and pressure)
0.48 liters at STP (standard temperature and pressure)