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Assuming all objects fall at the same pace at the same altitude, using Newton's formula of Gravity, F = G*m1*m2/r2.

G is the global gravity constant, m1 = 5.9736 × 1024 kg, m2 = 1kg (because it doesn't matter, all objects fall at the same pace, 1 is easier to calculate), and r2 = (earth's radius + 6100m)^2

After you put all those numbers, you get F =~ 9.8N. Since our object is 1kg of mass, that's also the acceleration (according to newton's 2nd law)

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Q: Calculate the effective value of the acceleration of gravity at 6100m above the earth's surface?
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