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Calculate the hang time of an athlete who jumps a vertical distance of 0.75 meter?
Wiki User
∙ 11y ago
What is the "hang time" of an athlete who can jump a vertical distance of 0.75 m? The athlete goes up 0.75 m, and then comes back down the same distance. Going up and coming down take the same time, so the hang time is twice the time for the athlete to fall 0.75 m from rest. How long is that? d = 0.75 m, a = 10 m/s2, t = ? The hang time is twice the time to fall = 2(0.385 s) = 0.77 s Check: http://www.batesville.k12.in.us/physics/phynet/mechanics/kinematics/answers/answers_sep_30.htm Hope you understand
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∙ 11y ago
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