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Calulate work done by 47 N force pushing a 0.025 kg pencil 0.25 m against a force of 23 N?
Wiki User
∙ 14y ago
A force of 47 N acting through a distance of 0.25 m does (47 x 0.25) = 11.75 joules of work.
It doesn't matter what kind of object is being moved, or what other forces may be involved
in the operation.
Wiki User
∙ 14y ago
Wiki User
∙ 13y agoWork is F x D (Force x Distance)
So all you have to do is multiply 47 by .26m.
The Answer comes out to be 12.22 Joules.
( I currently have this question on my Physics assignment right now as question 1 with the title Physics 11 - Work, Power, Energy Worksheet)
Anonymous
Wiki User
∙ 12y agoJust multiply the force times the distance. Result is in joules.
Wiki User
∙ 14y agow=f.d cos 0
w=47x0.26x1=12.22J
Anonymous
12:3
Anonymous
12.22J
Anonymous
Ft
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